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Stolb23 [73]
2 years ago
5

I need help quick it is too hard for me to answer

Mathematics
1 answer:
ANEK [815]2 years ago
6 0
A and C are true, I’m not sure about D.
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Anyone know how to solve this?
Dmitry_Shevchenko [17]

Answer:

whats the question..?

Step-by-step explanation:

7 0
3 years ago
What is the value of the expression-2(-3+-1)
Deffense [45]

Answer:

-4

Step-by-step explanation:

2(-3+1)

Distribute: -6 - (-2)

Answer: -4

3 0
4 years ago
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Chose one value for x and substitute the value in the equation to get your answer pick x=15 or x=12 or x=10 2x+13
lora16 [44]
If I pick 10, then 2(10)+13=33
If I pick 15, then 2(15)+13=43
If I pick 12, then 2(12)+13=37
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3 years ago
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Please due in 2 min NO LINKS
Ulleksa [173]

Answer:

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3 years ago
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A rectangular piece of metal is 25 in longer than it is wide. Squares with sides 5 in long are cut from the four corners and the
Licemer1 [7]

Answer:

The original length was 41 inches and the original width was 16 inches

Step-by-step explanation:

Let

x ----> the original length of the piece of​ metal

y ----> the original width of the piece of​ metal

we know that

When squares with sides 5 in long are cut from the four corners and the flaps are folded upward to form an open box

The dimensions of the box are

L=(x-10)\ in\\W=(y-10)\ in\\H=5\ in

The volume of the box is equal to

V=(x-10)(y-10)5

V=930\ in^3

so

930=(x-10)(y-10)5

simplify

186=(x-10)(y-10) -----> equation A

Remember that

The piece of metal is 25 in longer than it is wide

so

x=y+25 ----> equation B

substitute equation B in equation A

186=(y+25-10)(y-10)

solve for y

186=(y+15)(y-10)\\186=y^2-10y+15y-150\\y^2+5y-336=0

Solve the quadratic equation by graphing

using a graphing tool

The solution is y=16

see the attached figure

Find the value of x

x=16+25=41

therefore

The original length was 41 inches and the original width was 16 inches

3 0
4 years ago
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