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vaieri [72.5K]
4 years ago
9

Solve the following system of equations and show all work. y = -x^2 + 4 y = 2x + 1

Mathematics
1 answer:
Pavel [41]4 years ago
8 0
-x^2 + 4 = 2x + 1
-x^2 - 2x + 4 - 1 = 0
-x^2 - 2x + 3 = 0
(x + 3)(-x + 1)= 0

x + 3 = 0           -x + 1 = 0
x = -3                -x = -1
                          x = 1

so x = -3 and x = 1
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Can someone pls help??
Vlad1618 [11]

Answer:

a. The y coordinates for A are either 10 or -14

b.  The y coordinates for A are either -11 or 7

Step-by-step explanation:

distance = sqrt ((x2-x1)^2+(y2-y1)^2)

We know Point B and the x coordinate of point A as well as the distance

15 = sqrt ((-4-5)^2+(-2-y1)^2)

15 = sqrt ((-9)^2+(-2-y1)^2)

15 = sqrt (81+(-2-y1)^2)

Square each side

15^2 =sqrt (81+(-2-y1)^2)^2

225 =  81+(-2-y1)^2

Subtract 81 from each side

225-81 = 81-81 +(-2-y1)^2

144 = (-2-y1)^2

Take the square root of each side

±sqrt 144 = sqrt(-2-y1)^2

±12 = (-2-y1)

Add 2 to each side

2±12 = 2-2-y1

2±12 = -y1

14 = -y1  or -10 = -y1

Multiply by -1

-14 = y1  or 10 = y1

The y coordinates for A are either 10 or -14

Now move B to -7,-2

15 = sqrt ((-7-5)^2+(-2-y1)^2)

15 = sqrt ((-12)^2+(-2-y1)^2)

15 = sqrt (144+(-2-y1)^2)

Square each side

15^2 =sqrt (144+(-2-y1)^2)^2

225 =  144+(-2-y1)^2

Subtract 144 from each side

225-144 = 144-144 +(-2-y1)^2

81 = (-2-y1)^2

Take the square root of each side

±sqrt 81 = sqrt(-2-y1)^2

±9 = (-2-y1)

Add 2 to each side

2±9 = 2-2-y1

2±9 = -y1

11 = -y1  or -7 = -y1

Multiply by -1

-11 = y1  or 7 = y1

The y coordinates for A are either -11 or 7

3 0
3 years ago
Solve the equation: 6x - 8 = 2 + 9x - 1<br> A. 4<br> B. -6<br> C. -2<br> D. -3
madreJ [45]

Answer:

D

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Graph the equation y = -3x on a graph
Dafna1 [17]

Put a dot on the -3 from the y-axis and draw a straight line from left to right.

3 0
3 years ago
An English class attended a performance at the theater. The class took 25 students and 3 adults. Each student ticket, s, cost $3
Mashcka [7]

Answer:

A or d to narrow it down

Step-by-step explanation:

Hopefully you can figure out which one I am sorry.

7 0
3 years ago
if a right triangle has one side measuring 3√2 and another side measuring 2√3, what is the length of the hypotenuse?
lina2011 [118]

Answer:

<h2>\sqrt{30}</h2>

Step-by-step explanation:

Given,

Perpendicular ( p ) = 3√2

Base ( b ) = 2√3

Hypotenuse ( h ) = ?

Now, let's find the length of the hypotenuse:

Using Pythagoras theorem:

{h}^{2}  =  {p}^{2}  +  {b}^{2}

plug the values

{h}^{2}  =  {(3 \sqrt{2} )}^{2}  +  {(2 \sqrt{3} )}^{2}

To raise a product to a power, raise each factor to that power

{h}^{2}  = 9 \times 2 + 4 \times 3

Multiply the numbers

{h}^{2}  = 18 + 12

Add the numbers

{h }^{2}  = 30

Take the square root of both sides of the equation

h =  \sqrt{30}

Hope this helps...

Best regards!!

6 0
3 years ago
Read 2 more answers
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