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MrMuchimi
2 years ago
5

Evaluate 10m + n2/4 when m = 5 and n = 4

Mathematics
2 answers:
Vitek1552 [10]2 years ago
5 0

Answer:

10(5)+(4)2/4= 50 + 2

Step-by-step explanation:

10m when m = 5 equals 10(5) or 10 times 5

n2/4 when n = 4 equals (4)2/4 or 4 times 2/4

5 x 10 = 50

4 x 2/4 = 2 which then equals

50 + 2 = 52

hope thats right and it helps! <3

posledela2 years ago
4 0

Answer:

52 units

Step-by-step explanation:

1) 10m + n2/4

Substitute within the equation

2) 10(5) + (4)2/4
Simplify

3) 50 + (4 x 2/4) = 50 + (4 x 1/2) = 50 + 2 = 52 units

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2 years ago
Use Remainder Theorem to determine if x-2 is a factor of the polynomial f(x)=3x^5 - 7x^3 -
morpeh [17]

<u>Answer:</u>

(x - 2) is not a factor of f(x)  = 3x^5 - 7x^3 -  11x^2 + 2

<u>Step-by-step explanation:</u>

According to the Remainder Theorem, when a polynomial f(x) is divided by a term (x - r), then the remainder must be f(r).

So first we will divide f(x) by (x - 2) using long division to get:

(3x^5 - 7x^3 -  11x^2 + 2) / (x - 2)

= 3x^4 + (6x^4 - 7x^3 - 11x^2 + 2) / (x-2)

= 3x^4 + 6x^3 + (5x^3-11x^2+2) / (x - 2)

= 3x^4 + 6x^3 + 5x^2 (-x^2 + 2) / (x - 2)

= 3x^4 + 6x^3 + 5x^2 -x -2 - (2) / (x -2)

= \frac{-2 + 3x^{5} - 7x^{3} - 11x^{2} + 2x}{x - 2} - 2

Therefore the remainder is -2.

Now check x = 2 for 3x^5 - 7x^3 -  11x^2 + 2:

3(2)^5 - 7(2)^3 -  11(2)^2 + 2 = -2

The Remainder Factor theorem also states that if (x - r) is a factor of f(x) then f(r) must be 0.

So we found that f(2) = -2, therfore (x - 2) is not a factor of f(x) .


3 0
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Read 2 more answers
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