PLEASE HELP ILL GIVE BRAINLIEST Find the square root of the number. 2square root –16

Mathematics

2 answers:

son4ous [18]3 years ago

7 0

Answer:

2(4i)

the square root of negative number is imaginary

givi [52]3 years ago

3 0

Answer: 4

Step-by-step explanation:

You might be interested in

James, Ryan and Jill share £120 in the ratio 3:2:1.<br> Find out how much each person recieves.

ArbitrLikvidat [17]

Answer:

James = £60, Ryan = £40 and Jill = £20

Step-by-step explanation:

James - 3, Ryan - 2 and Jill - 1

3 + 2 + 1 = 6

£120 / 6 = 20

Times 20 by each of the three numbers (3, 2 and 1)

3 x 20 = £60 (James)

2 x 20 = £40 (Ryan)

1 x 20 = £20 (Jill)

8 0

3 years ago

Read 2 more answers

Plz with steps .. it's very hard can anyone plz

liubo4ka [24]

Answer:

Step-by-step explanation:

$\displaystyle\ \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\frac{0}{0} \\\\we\ can \ use\ Hospital's\ Rule\\\\\\f(x)=\sqrt{2x}-\sqrt{3x-a} \qquad f'(x)=\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} \\\\g(x)=\sqrt{x} -\sqrt{a} \qquad g'(x)=\dfrac{1}{2\sqrt{x}} \\\\\\\displaystyle\ \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\lim_{n \to a} \dfrac{\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} }{\dfrac{1}{2\sqrt{x}} }\\\\$

$\displaystyle \lim_{n \to a} \dfrac{2\sqrt{x} }{\sqrt{2x}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}} =\lim_{n \to a} \dfrac{2 }{\sqrt{2}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3*\sqrt{a} }{\sqrt{2a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3}{\sqrt{2}}\\\\\\=-\ \dfrac{1}{\sqrt{2}}\\\\$