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Tom [10]
2 years ago
11

What should be added to (-5 a2b - 9 ab) to get a2b + 3 ab?​

Mathematics
1 answer:
Doss [256]2 years ago
5 0

Based on given conditions,

a²b + 3 ab - (-5 a²b - 9 ab)

→a²b + 3 ab + 5 a²b + 9 ab

→(a²b + 5 a²b) + (3ab + 9 ab

Now collecting the coefficients and adding them,

(1 + 5)a²b + (3 + 9)ab

→6 {a}^{2}b + 12ab

Hence, the <u>6</u><u>a</u><u>²</u><u>b</u><u> </u><u>+</u><u> </u><u>1</u><u>2</u><u>a</u><u>b</u> should be added.

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If 2x2 + y2 = 17 then evaluate the second derivative of y with respect to x when x = 2 and y = 3. Round your answer to 2 decimal
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Answer:

y''=-1.26

Step-by-step explanation:

We are given that 2x^2+y^2=17

We have evaluate the second order derivative of y w.r.t. x when x=2 and y=3.

Differentiate w.r.t x

Then , we get

4x+2yy'=0

2x+yy'=0

yy'=-2x

y'=-\frac{2x}{y}

Again differentiate w.r.t.x

Then , we get

2+(y')^2+yy''=0 (u\cdot v)'=u'v+v'u)

2+(y')^2+yy''=0

Using value of y'

yy''=-2-(-\frac{2x}{y})^2

y''=-\frac{2+(-\frac{2x}{y})^2}{y}

Substitute x=2 and y=3

Then, we get y''=-\frac{2+(\frac{4}{3})^2}{3}

y''=-\frac{18+16}{9\times 3}=-\frac{34}{27}

Hence,y''=-1.26

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Answer:

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