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tiny-mole [99]
3 years ago
7

Given the function f(x) = 3(x – 2)2 + 4 with a restricted domain of x ≥ 2, which of the following represents f–1(x)?.

SAT
1 answer:
Debora [2.8K]3 years ago
6 0

The inverse of the function is f^{-1}x= \sqrt{\frac{x-4}{3} } + 2

<h3 /><h3>Domain and Range of functions</h3>

Given the function

f(x) = 3(x - 2)^2 + 4

To get the inverse, you will follow the same step as shown:

Rewrite the equation to have:

y= 3(x - 2)^2 + 4

Replace x with y

x = 3(y - 2)^2 + 4

<h3>Make y the subject of the formula</h3>

x = 3(y - 2)^2 + 4\\x-4=3(y - 2)^2\\\frac{x-4}{3} = (y-2)^2\\ y-2=\sqrt{\frac{x-4}{3} } \\y = \sqrt{\frac{x-4}{3} } + 2

Hence the inverse of the function is f^{-1}x= \sqrt{\frac{x-4}{3} } + 2

Learn more on inverse of a function here: brainly.com/question/2873333

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