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krok68 [10]
2 years ago
8

What number should be added to the expression x2 14x to change it into a perfect square trinomial?.

Mathematics
1 answer:
makkiz [27]2 years ago
8 0

Answer:

  49

Step-by-step explanation:

When you look at the square of a binomial, you see ...

  (x +a)^2 = x^2 +(2a)x +a^2

The constant value (a^2) is <em>the square of half the x-coefficient</em>.

  (14/2)^2 = 49 . . . . the value to be added.

Adding 49 gives ...

  x^2 +14x +49 = (x +7)^2

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5x + 7y = 25<br> 5x - 2y = -65<br> solve using elimination<br> (step by step please)
aliina [53]

5x+7y=25

5x-2y=-65

subtract both of the equations

5x-5x=0

7y--2y= 7y+2y=9y

25--65=25+65=90

0+9y=90

9y=90

divide both sides by 9 to get y by itself

9y/9=90/9

cross out 9 and 9 which becomes 1*1*y=y

90/9=10

y=10

find x by using the substitution method

5x+7y=25

5x+7(10)=25

5x+70=25

move +70 to the other side

sign changes from +70 to -70

5x+70-70=25-70

5x=-45

divide both sides by 5 to get x by itself

5x/5=-45/5

cross out 5 and 5 then becomes 1*1*x=x

-45/5=-9

x=-9

answer:

(-9,10)

6 0
3 years ago
What is the precent of increase from 5 to 6?
Law Incorporation [45]

Answer:

20

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Find an equation for the nth term of the arithmetic sequence. -15, -6, 3, 12, ...
Mariulka [41]

Answer: t_{n}=-15+9(n-1)

Step-by-step explanation:

The formula for finding the nth term of an arithmetic sequence is given as:

t_{n}=a+(n-1)d

a = first term = -15

d = common difference = -6 - (-15) = 9

n = number of terms

substituting into the formula , we have :

t_{n} = -15+(n-1)9

t_{n}=-15+9(n-1)

5 0
2 years ago
WILL GIVE A BRAINLIEST PLEASE HELP!!!
kaheart [24]
A(n) = a₁.(r)ⁿ⁻¹, where a₁ = 1st term, r= common ratio and n, the rank

In the formula given a₁ = 5, r = 3/2 and n = 6 (we have to find the 6th term value).

a₆ = 5.(3/2)⁶⁻¹ = 5.(3/2)⁵ = 1215/32 (answer C)
7 0
3 years ago
Determine algebraically whether the given function is even, odd, or neither.
uranmaximum [27]
To check whether a function is odd or even, we simply substitute the argument by its negative version, namely "x" by "-x".

if the expression simplifies to resemble the original expression, that simply means the expression is even.  If it resembles the original negative expression, is odd.

\bf g(x)=-2x^3-9\\\\&#10;-------------------------------\\\\&#10;\stackrel{x=-x}{g(-x)}=-2(-x)^3-9\implies g(-x)=-2(-x)(-x)(-x)-9&#10;\\\\\\&#10;g(-x)=+2(x)(x)(x)-9\implies g(-x)=2x^3-9

 well, that doesn't look like the original - 2x³ - 9, so is not even.

and -f(x) would be 2x³ + 9, and that doesn't look like either, so is not odd.

thus is neither.
7 0
3 years ago
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