180^2 + 235^2 = (cliff base to point on bridge)^2
32400 + 55225 = 87625
so cliff base to point on bridge = sqrt of 87625.
Then notice 87625 + d^2 = (x+180)^2
since x^2 +235^2 = d^2,
substitute (x^2 + 235^2) for d^2, like this:
87625 + x^2 + 235^2 = (x+180)^2
87625 + x^2 + 55225 = x^2 + 360x + 32400
87625 + 55225 - 32400 = x^2 - x^2 +360x
360x = 110450
x = about 306.8 feet
h = x+180, so h = 486.8 feet
Remember d^2 = x^2 + 235^2, so
d^2 = 306.8^2 + 235^2
d^2 = 149354.6489
d = about 386.46 feet

6 0

3 years ago

At one gym, there is a $12 start-up fee, and after that each month, m, at the gym costs $20. At another gym, each month at the g

Galina-37 [17]

Answer: it will take 6 months for both gyms to cost the same.

Step-by-step explanation:

Let m represent the number of months that it will take for the cost of both gyms be the same.

At one gym, there is a $12 start-up fee, and after that each month, m, at the gym costs $20. This means that the total cost for m months is

12 + 20m

At another gym, each month at the gym costs $22. This means that the total cost for m months is 22m

For both costs to be the same, the number of months would be

12 + 20m = 22m

22m - 20m = 12

2m = 12

m = 12/2 = 6

3 0

3 years ago

Find the coordinates of the midpoint of a segment with the endpoints (16,5) & (28,-13)

frutty [35]

$\text{The formula of the midpoint of a segment with the end points:}\\\\A(x_A;\ y_A)\ \text{and}\ B(x_B;\ y_B)\\\\M_{AB}=\left(\dfrac{x_A+x_B}{2};\ \dfrac{y_A+y_B}{2}\right)$

$\text{We have:}\\A(16;\ 5)\to x_A=16;\ y_A=5\\B(28;\ -13)\to x_B=28;\ y_B=-13\\\\\text{substitute:}\\\\M_{AB}=\left(\dfrac{16+28}{2};\ \dfrac{5+(-13)}{2}\right)=\left(\dfrac{44}{2};\ \dfrac{-8}{2}\right)=(22;\ -4)$

7 0

3 years ago