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nasty-shy [4]
3 years ago
8

What are the 2 most dangerous computer viruses?

Computers and Technology
2 answers:
Tems11 [23]3 years ago
7 0

Answer: Klez. Klez was written in Microsoft Visual C++ and was one of the most disastrous computer viruses in history.

Sasser. Sasser was first discovered in April of 2004.

Explanation:

Afina-wow [57]3 years ago
6 0

Answer:

there are a lot of computer virus, but the most dangerous computer viruses are code red and sasser

Explanation:

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<h3>What are the three main causes of a data breach?</h3>

A hack, such as phishing or stolen credentials; a mistake, such as lost devices or wrong system configuration; or a physical attack, such as a skimmer at a gas station pump that collects credit card data, all resulted in data being exposed or stolen.

Thus, due to there is not an enforcement of security.

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7 0
2 years ago
As a chemical engineer, what would you be most likely to do in your job?
stealth61 [152]

Answer:

The correct option is;

Design sewer treatment plants

Explanation:

Chemical engineers, also known as a process engineer, are involved in the design and development of cost beneficial ways of utilizing energy and materials which can mostly be established as a chemical manufacturing process

The chemical engineer works by applying scientific principles to resolve and provide amicable solutions to the production usage, disposal, and waste management, of chemical and other related materials

Chemical engineers conducts research into the usage of materials and production process.

6 0
3 years ago
How many basic elements of QBASIC are there
Masteriza [31]
<h2>6</h2>

The elements used in Qbasic:

  • Character set.
  • Variables.
  • Constants.
  • Operator and Operands.
  • Expression.
  • Statements.
6 0
3 years ago
Hw to gain more knowledge ​
LenaWriter [7]

Answer:

Read Books, Search the Internet, etc...

Explanation:

6 0
3 years ago
Write a code that calculates the Greatest Common Divisor (GCD) of two positive integers (user-defined inputs). Include an except
STALIN [3.7K]

Answer:

<em>This program is written using Java programming language</em>

import java.util.*;

public class calcGcd

{

   public static void main (String [] args)

   {

       int num1, num2;

       Scanner input = new Scanner(System.in);

       //Input two integers

       num1 = input.nextInt();

       num2 = input.nextInt();

       //Get least of the two integers

       int least = num1;

       if(num1 > num2)

       {

           least = num2;

       }

       //Initialize gcd to 1

       int gcd = 1;

       //Calculate gcd using for loop

       for(int i=1;i<=least;i++)

       {

           if(num1%i == 0 && num2%i == 0)

           {

               gcd = i;

           }

       }

       if(gcd == 1)

       {

           System.out.print("GCD is 1");

       }

       else

       {

           System.out.print("GCD is "+gcd);

       }

   }

}

Explanation:

To calculate the GCD, the program uses a for loop that iterates from 1 to the smaller number of the user input.

Within this iteration, the program checks for a common divisor of the two user inputs by the iterating element

The GCD is then displayed afterwards;

However, if the GCD is 1; the program prints the message "GCD is 1"

<em>Line by Line Explanation</em>

This line declares two integer numbers

       int num1, num2;

This line allows user the program to accept user defined inputs        

Scanner input = new Scanner(System.in);

The next two line allows gets inputs from the user

<em>        num1 = input.nextInt();</em>

<em>        num2 = input.nextInt();</em>

<em />

To calculate the GCD, the smaller of the two numbers is needed. The smaller number is derived using the following if statement

<em>        int least = num1;</em>

<em>        if(num1 > num2)</em>

<em>        {</em>

<em>            least = num2;</em>

<em>        }</em>

The next line initializes GCD to 1

       int gcd = 1;

The GCD is calculated using the following for loop

The GCD is the highest number that can divide both numbers

<em>        for(int i=1;i<=least;i++)</em>

<em>        {</em>

<em>            if(num1%i == 0 && num2%i == 0)</em>

<em>            {</em>

<em>                gcd = i;</em>

<em>            }</em>

<em>        }</em>

The following is printed if the calculated GCD is 1

       if(gcd == 1)

       {

           System.out.print("GCD is 1");

       }

Otherwise, the following is printed

       else

       {

           System.out.print("GCD is "+gcd);

       }

8 0
3 years ago
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