Answer:
see explaination
Explanation:
#include <iostream>
#include <string>
using namespace std;
class LinkedList{
class Node{
public :
int data;
Node* next;
Node(int data){
this->data = data;
next = NULL;
}
};
public :
Node *head;
LinkedList(){
this->head = NULL;
}
void insert(int d){
Node* new_node = new Node(d);
new_node->next = head;
head = new_node;
}
// sort the list with selection sort algorithm.
// Pick the smallest element in the unsorted array and place in the first element in the unsorted.
void sort_list(){
if (head == NULL){
return;
}
Node* current = head;
while (current->next != NULL){
Node* min_node = current;
Node* traverse = current->next;
while(traverse != NULL){
if(traverse->data < min_node->data){
min_node = traverse;
}
traverse = traverse->next;
}
int temp = current->data;
current->data = min_node->data;
min_node->data = temp;
current = current->next;
}
}
void print_list(){
Node* current = head;
while(current !=NULL){
cout<<current->data<<" ";
current = current->next;
}
cout<<"\n";
}
};
int main(){
LinkedList ll;
for(int i=0;i<10;i++){
ll.insert(i);
}
ll.print_list();
cout<<"*******************************************\n";
ll.sort_list();
ll.print_list();
cout<<"*******************************************\n";
}
Answer:
Option B is correct.
Explanation:
Within Techno Info Systems the user has been analyst contemplating that four-model concept towards computer development for such its new customer. When they adopt that four-model method, thus the result seems to be the time taken to implement the rises in the method.
So, therefore the other options are incorrect according to the following scenario.
Answer:
1010 0111 1101 1111
Explanation:
A = 10 in decimal = 1010 in binary
7 = 7 in decimal = 0111 in binary
D = 13 in decimal = 1101 in binary
F = 15 in decimal = 1111 in binary
Therefore 0xA7DF = 1010 0111 1101 1111 in binary
chxgfk hcyskvuct auhchovuzq vuvscisv
1. Answer is B (D9=<span>A2+B3)
2. </span><span>C. identifies how many cells with data were in the range
3. </span><span>A. ascending (smallest to largest)
</span><span>4. A. the current worksheet </span>
