According to a center for disease control. We can’t compute the probability.
<u>SOLUTION:
</u>
Given that, According to a center for disease control,
The probability that a randomly selected person has hearing problems is 0.157.
The probability that a randomly selected person has vision problems is 0.096.
We have to find whether we can compute the probability of randomly selecting a person who has hearing problems or vision problems by adding these probabilities or not?
The answer is no, because hearing and vision problems are not mutually exclusive.
So, some people have both hearing and vision problems.
These people would be included twice in the probability.
Hence, we can’t compute the probability.
Answer:
a
Step-by-step explanation:
Answer:
x = - 3
Step-by-step explanation:
Given
7 + x - 3 = x - 5 - 3x ( simplify both sides )
4 + x = - 2x - 5 ( add 2x to both sides )
4 + 3x = - 5 ( subtract 4 from both sides )
3x = - 9 ( divide both sides by 3 )
x = - 3
Answer:
The number of different lab groups possible is 84.
Step-by-step explanation:
<u>Given</u>:
A class consists of 5 engineers and 4 non-engineers.
A lab groups of 3 are to be formed of these 9 students.
The problem can be solved using combinations.
Combinations is the number of ways to select <em>k</em> items from a group of <em>n</em> items without replacement. The order of the arrangement does not matter in combinations.
The combination of <em>k</em> items from <em>n</em> items is: 
Compute the number of different lab groups possible as follows:
The number of ways of selecting 3 students from 9 is = 
Thus, the number of different lab groups possible is 84.
Answer:
26 and 11
Step-by-step explanation:
When your add them you get 37, and when you multiply 26 by two you get 52. 52-11 is 41.
