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Marina86 [1]
3 years ago
13

When text is longer than the width of a column, Excel displays the overflow characters in adjacent cells to the right as long as

those adjacent cells contain no data. True
Biology
1 answer:
Fiesta28 [93]3 years ago
7 0
The statement is True.

In Microsoft Office Excel, when the text inside a cell is longer than the width of the cell it overflows the display on the next adjacent cell on the right as long as its an empty cell. If there is a data, the other text will be hidden unless you click on Wrap text.
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An embryologist is looking at a cross-section of a mouse embryo. she notices that flanking either side of the neural tube (the r
Studentka2010 [4]

The answer is ganglia. As indicated, they house many cell bodies of afferent and efferent neurons. Spinal ganglia are located in the dorsal (that contain cell bodies of afferent neurons) and ventral roots (that house cell body of efferent neurons) of a spinal nerve.






5 0
3 years ago
Describe the factors that affect the paths of secondary succession.
inna [77]

Answer:

Human disturbances such as clear-cutting can also cause secondary succession. Some disturbances affect only a small area, like the local damage caused by a single tree falling in the forest, while others affect entire landscapes. These disturbances damage the ecosystem but leave soil and nutrients behind.

Explanation:

Trust me.

3 0
3 years ago
For this question, we will utilize a population of Martians that is in Hardy Weinberg Equilibrium. The dominant Martian phenotyp
Brrunno [24]

Answer:

d.0.48

Explanation:

When a population is in Hardy Weinberg equilibrium the <u>genotypic </u>frequencies are:

freq (AA) = p²

freq (Aa) = 2pq

freq (aa) = q²

<em>p</em> is the frequency of the dominant <em>A</em> allele and <em>q</em> is the frequency of the recessive <em>a</em> allele.

In this population of 100 individuals, 84 martians have the dominant phenotype and 16 have the recessive phenotype.

Therefore:

q²=16/100

q² = 0.16

q=√0.16

q = 0.4

And p+q=1, so:

p = 1 - q

p = 1-0.4

p = 0.6

The frequency of heterozygotes is:

freq (Aa) = 2pq = 2 × 0.4 × 0.6

freq (Aa) = 0.48

5 0
3 years ago
What is a fossa bone marking
sashaice [31]

Answer:

In the first level courses in human anatomy and the related health sciences, bone marks and bone features (including the proper terms for their description) are also important. To interact efficiently with practitioners interested in healthcare, science, forensics and related fields, it is important to be familiar with the language used for bone markings.

4 0
3 years ago
Suppose that a glutamine residue in the active site of an enzyme was mutated to alanine. As expected, the alanine mutant was ina
likoan [24]

Answer:

A to N

Explanation:

Glutamine is an amino acid with a polar, uncharged side chain. The mutation to alanine, an amino acid with a non-polar side chain, completely affects the enzymatic activity. This makes sense considering the difference in the nature of both amino acids.

To restore the wild-type level of activity the alanine would have to mutate to another polar uncharged amino acid. Among the given options, only Asparagine (N) has a similar chemistry to Glutamine.

7 0
4 years ago
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