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2 years ago

PLS HELP CAN’T FIGURE OUT HOW TO FIND b OR c ASAPPPPPPPPP

Mathematics

1 answer:

natita [175]2 years ago

5 0

Answer:

b = 0.35 ; c = 2.03

Step-by-step explanation:

tan = opposite/hypotenuse

Therefore, tan (10) = b/2

b = 2 tan (10) = about 0.35

Use the Pythagorean theorem to find that c = 2.03

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Can someone please help me ;-; this is due today

IRISSAK [1]

Answer:

The correct answer: F (Scalene) and A (Acute)

Step-by-step explanation:

F. (Scalene): By definition, a scalene triangle is a triangle that has no equal sides, and no equal angles. This definition matches your given triangle, since it has no equal sides and angles.

A. (Acute): By definition, an acute triangle is a triangle in which all the internal angles are less than 90 degrees. This definition matches your given triangle, since all of the internal angles are less than 90 degrees.

The given triangle is not obtuse, equilateral, right, and isoceles.

It is not an obtuse triangle because none of the angles are greater than 90 degrees.

It is not an equilateral triangle because its sides are not equal.

It is not a right triangle because none of its internal angles measure 90 degrees.

And it is not an isoceles triangle because by definition, an isoceles triangle must have two equal sides. Your given triangle has no equal sides.

6 0

3 years ago

rachel jogged along a trail that was 1/4 of a mile long. She jogged along the trail 8 times. how many miles did rachel jog?

____ [38]

To solve for how many miles Rachel jogged if she jogged a 1/4 mile trail 8 times, we simply need to multiply the distance she ran each time by the amount of times she ran it.

1/4 * 8 = 2

Rachel jogged 2 miles.
Hope that helped =)

4 0

3 years ago

1. Write the form of the partial fraction decomposition of the rational expression. Do not solve for the constants.

german

Answer:

Step-by-step explanation:

To write the form of the partial fraction decomposition of the rational expression:

We have:

$\mathbf{\dfrac{8x-4}{x(x^2+1)^2}= \dfrac{A}{x}+\dfrac{Bx+C}{x^2+1}+\dfrac{Dx+E}{(x^2+1)^2}}$

Using partial fraction decomposition to find the definite integral of:

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}dx$

By using the long division method; we have:

$x^2-8x-20 | \dfrac{2x}{2x^3-16x^2-39x+20 }$

$- 2x^3 -16x^2-40x$

$x+ 20$

So;

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x+\dfrac{x+20}{x^2-8x-20}$

By using partial fraction decomposition:

$\dfrac{x+20}{(x-10)(x+2)}= \dfrac{A}{x-10}+\dfrac{B}{x+2}$

$= \dfrac{A(x+2)+B(x-10)}{(x-10)(x+2)}$

x + 20 = A(x + 2) + B(x - 10)

x + 20 = (A + B)x + (2A - 10B)

Now; we have to relate like terms on both sides; we have:

A + B = 1 ; 2A - 10 B = 20

By solvong the expressions above; we have:

$A = \dfrac{5}{2}$ $B = \dfrac{3}{2}$

Now;

$\dfrac{x+20}{(x-10)(x+2)} = \dfrac{5}{2(x-10)} + \dfrac{3}{2(x+2)}$

Thus;

$\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)}$

Now; the integral is:

$\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx = \int \begin {bmatrix} 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)} \end {bmatrix} \ dx$

$\mathbf{\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx = x^2 + \dfrac{5}{2}In | x-10|\dfrac{3}{2} In |x+2|+C}$

3. Due to the fact that the maximum words this text box can contain are 5000 words, we decided to write the solution for question 3 and upload it in an image format.

Please check to the attached image below for the solution to question number 3.