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Angelina_Jolie [31]
3 years ago
7

Use the original price and the markup to find the retail price.

Mathematics
1 answer:
Bond [772]3 years ago
6 0

Answer:

50.6

Step-by-step explanation:

46*.1=4.6

46+4.6=50.6

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x = 3, the error is that the -2x should be added.

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Answer lest edited 3:11 PM Central, 11/24/2020

4 0
3 years ago
Read 2 more answers
(3squared)squared x(10cubed)squared
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\tt {(3 ^{2} )}^{2}  \times  {(10^{3}) }^{2}  \\ \tt  = (3 \times 3) ^{2}  \times  {(10 \times 10 \times 10)}^{2}  \\   \tt \: =  {9}^{2}  \times 1000 ^{2}  \\ \tt  = (9 \times 9) \times (1000 \times 1000) \\  = \tt \:  81  \times  1000000 \\  =  \boxed{\tt \:  81000000}

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Read 2 more answers
I’m Really lost if I could get a answer it would be greatly appreciated
Nataly [62]
<h3>Answers:</h3>

f(g(x)) = \sqrt{x^2+5}+5\\\\g(f(x)) = x+30+10\sqrt{x-1}

================================================

Work Shown:

Part 1

f(x) = \sqrt{x-1}+5\\\\f(g(x)) = \sqrt{g(x)-1}+5\\\\f(g(x)) = \sqrt{x^2+6-1}+5\\\\f(g(x)) = \sqrt{x^2+5}+5\\\\

Notice how I replaced every x with g(x) in step 2. Then I plugged in g(x) = x^2+6 and simplified.

------------------

Part 2

g(x) = x^2+6\\\\g(f(x)) = \left(f(x)\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}+5\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}\right)^2+2*5*\sqrt{x-1}+\left(5\right)^2+6\\\\g(f(x)) = x-1+10\sqrt{x-1}+25+6\\\\g(f(x)) = x+30+10\sqrt{x-1}\\\\

In step 4, I used the rule (a+b)^2 = a^2+2ab+b^2

In this case, a = sqrt(x-1) and b = 5.

You could also use the box method as a visual way to expand out \left(\sqrt{x-1}+5\right)^2

6 0
3 years ago
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