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amid [387]
2 years ago
13

A baker paid $15.05 for flour at a store that sells flour for $0.86 per pound.How many pounds of flour did the baker buy

Mathematics
1 answer:
Wittaler [7]2 years ago
5 0

Answer:

17.5 pounds

Step-by-step explanation:

\frac{15.05}{0.86} = 17.5

Hence, the baker buy 17.5 pounds of flour.

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4. Bobbie scores m marks in a test. <br> Georgia scores three times as many marks as Bobbie.
xxTIMURxx [149]

Marks of Bobbie = x

Then, marks of Georgia

= 3 times marks of Bobbie

= 3 times m

= 3 × m

= 3m

6 0
3 years ago
(2,0) (3,9) equation
valkas [14]

Answer: if ur  trying to do the equation for coordinate planes its

Y2-y1.

                 X1-x2

Step-by-step explanation:

That's what i was taught I'm in 8th grade tho so

6 0
4 years ago
A gumball has a diameter that is 66 mm. The diameter of the gumball's spherical hollow core is 58 mm. What is the volume of the
grigory [225]

Answer:

Volume of gumball without including its hollow core is 48347.6 cubic mm.

Step-by-step explanation:

Given:

Diameter of Gumball = 66 mm

Since radius is half of diameter.

Radius of gumball = \frac{diameter}{2}=\frac{66}{2} =33 \ mm

Now We will first find the Volume of Gumball.

To find the Volume of Gumball we will use volume of sphere which is given as;

Volume of Sphere = \frac{4}{3}\pi r^3

Now Volume of Gumball = \frac{4}{3}\times3.14 \times (33)^3 = 150456.24 \ mm^3

Also Given

Diameter of gumball's spherical hollow core = 58 mm

Since radius is half of diameter.

Radius of gumball's spherical hollow core = \frac{diameter}{2}=\frac{58}{2} =29 \ mm

Now We will find the Volume of gumball's spherical hollow core.

Volume of Sphere = \frac{4}{3}\pi r^3

So Volume of gumball's spherical hollow core = \frac{4}{3}\times3.14 \times (29)^3 = 102108.61 \ mm^3

Now We need to find volume of the gumball without including its hollow core.

So, To find volume of the gumball without including its hollow core we would Subtract Volume of gumball spherical hollow core from Volume of Gumball.

volume of the gumball without including its hollow core = Volume of Gumball - Volume of gumball's spherical hollow core = 150456.24\ mm^3 - 102108.61\ mm^3 = 48347.63\ mm^3

Rounding to nearest tenth we get;

volume of the gumball without including its hollow core = 48347.6\ mm^3

Hence Volume of gumball without including its hollow core is 48347.6 cubic mm.

8 0
3 years ago
In the figure, find m∠RST if m∠RSU = 81° and m∠UST = 18°. Answers : A) 109° B) 81° C) 99° D) 63°
ohaa [14]
C because you add the angles together
6 0
3 years ago
Read 2 more answers
Wegnerkolmp2741o plz help me only wegnerkolmp2741o
34kurt

Answer:

1. Triangular prism

  • 5 faces
  • 6 vertices
  • 9 edges

2. Trapezoidal prism

  • 6 faces
  • 8 vertices
  • 12 edges

3. Pentagonal prism

  • 7 faces
  • 10 vertices
  • 15 edges

4. Hexagonal prism

  • 8 faces
  • 12 vertices
  • 18 edges

7 0
4 years ago
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