54, 36, 24 are the 1st 3 element of a geometric progression with 2/3 as a common ratio: PROOF:
the 1st term is 54, (a₁= 54) the 2nd term a₂ = 24, then
(a₂ = a₁.r) or 36 = 54.r → r= 36/54 = 2/3. Same logique for the 3rd term.
So 2/3 is common ratio. We know that :U(n) = a.(r)ⁿ⁻¹. Then if a =54 and r = x (given by the problem), then f(x) = 54.xⁿ⁻¹
n, being the rank of any element of this geometric progression
Answer:
= -6
Step-by-step explanation:
sngdmmgngngngngngngngngngngnfbfbfbfbfbfbf
Answer:
3(x - 10)
Step-by-step explanation:
3x - 30 = 3(x - 10)
The equation of a circle is:
(x-h)2 + (y-k)2 = r2
where (h,k) is the location of the center and r is the radius. So we need to find h, k, and r. The center is given as (5,-4) so h = 5 and k = -4:
(x-5)2 + (y-(-4))2 = r2
(x-5)2 + (y+4)2 = r2
So we need to find r. Use the distance formula to find the distance between (5,-4) and (-3,2):
r = [(5-(-3))2+((-4)-2)2]1/2
r = [82 + (-6)2]1/2
r = [64 + 36]1/2
r = 1001/2
r= 10
The final equation is:
(x-5)2 + (y+4)2 = 102
