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tatiyna
3 years ago
7

Factor: 4tan^2x-(4)/(cotx)+sinx(cscx) ...?

Mathematics
1 answer:
lisov135 [29]3 years ago
8 0
4tan^(2)x-((4)/(cotx))+sinxcscx 


Multiply -1 by the (4)/(cotx) inside the parentheses. 

4tan^(2)x-(4)/(cotx)+sinxcscx 


To add fractions, the denominators must be equal. The denominators can be made equal by finding the least common denominator (LCD). In this case, the LCD is cotx. Next, multiply each fraction by a factor of 1 that will create the LCD in each of the fractions. 


4tan^(2)x*(cotx)/(cotx)-(4)/(cotx)+sin... 


Complete the multiplication to produce a denominator of cotx in each expression. 

(4tan^(2)xcotx)/(cotx)-(4)/(cotx)+(cot... 


Combine the numerators of all expressions that have common denominators. 
<span>
(4tan^(2)xcotx-4+cotxsinxcscx)/(cotx)</span>
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grin007 [14]

Answer:

Point B

Step-by-step explanation:

Lines given:

  • y= 2/5x - 1/2
  • y= -1/3x +2/3

x coordinate of intersection of given lines is:

  • 2/5x - 1/2= -1/3x+2/3
  • 2/5x+1/3x= 2/3 +1/2
  • 6/15x+5/15x= 4/6+3/6
  • 11/15x=7/6
  • x= 7*15/11*6
  • x= 35/22

For this value of x, the value of y is:

  • y= 2/5*35/22 - 1/2
  • y=14/22- 1/2
  • y= 3/22

As per graph point (35/22, 3/22) is point B

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3 years ago
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zimovet [89]

Answer:

-x - 3

Step-by-step explanation:

7 0
3 years ago
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1/14 is you answer
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www.calculatorsoup.com



3 0
4 years ago
The article "Occurrence and Distribution of Ammonium in Iowa Groundwater" (K. Schilling, Water Environment Research, 2002:177–18
Papessa [141]

Answer: 95% confidence interval for the difference between the proportions would be (1.31, 1.39).

Step-by-step explanation:

Since we have given that

Number of alluvial wells = 349

Number of quaternary wells = 143

Number of alluvial wells that had concentrations above 0.1 = 182

Number of quaternary wells that had concentrations above 0.1 = 112

Average of alluvial wells = 0.27

Standard deviation = 0.4

Average of quaternary wells = 1.62

Standard deviation =1.70

So, 95% confidence interval gives

alpha = 5% level of significance.

\dfrac{\alpha}{2}=2.5\%\\\\z_{\frac{\alpha}{2}}=1.96

So, 95% confidence interval becomes,

(1.62-0.27)\pm 1.96\sqrt{\dfrac{0.4^2}{349}+\dfrac{1.7^2}{143}}\\\\=1.35\pm 1.96\times 0.020\\\\=(1.35-0.040,1.35+0.040)\\\\=(1.31,1.39)

Hence, 95% confidence interval for the difference between the proportions would be (1.31, 1.39).

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3 years ago
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