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Basile [38]
2 years ago
9

Monica and Lauren know that they will need a lot of money in order to make the purchases necessary for a successful bakery. They

decide to save money each week, and once each person has contributed an equal amount to the bakery's checking account, they will have enough to move forward with their business.
Monica does not initially put any money into the account but plans to deposit $153.46 per week.

Lauren decides to put an initial amount of $128.90 into the account plus deposit an additional $127.68 per week.

Develop a model to determine the number of weeks it will take for the girls to have deposited an equal amount of money. Based on that model, enter the total amount of money in the joined account after the correct number of weeks.
Mathematics
1 answer:
xxTIMURxx [149]2 years ago
4 0

Based on the model, the total amount of money in the joined account after the 5 weeks is $767.30

<h3>What are linear equations</h3>

Linear equations are equations that have constant rates

A linear equation is represented as:

y = mx+ b

In this case,

  • m represents the deposit per week
  • b represents the initial deposit

So, the linear equations are:

  • y =153.46x --- for Monica
  • y = 128.90+ 127.68x -- For Lauren

To calculate the number of weeks, when they have the same amount, we equate both equations

153.46x = 128.90 + 127.68x

Collect like terms

153.46x -127.68x= 128.90

25.78x= 128.90

Solve for x

x= 5

Substitute 5 for x in

y = 153.46x

y = 153.46 * 5

y = 767.30

Hence, it will take 5 weeks for both accounts to have the same amount of $767.30

Read more about linear equations at:

brainly.com/question/14323743

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for 12-8: 33.33

or

for 8-4: 50

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for 12-4: 66.67

Step-by-step explanation:

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3 years ago
Need help ASAP DUE SOON AND PLEASE SHOW WORk!!!!
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Answer:

87.92 inches cubed or 87.92 in.^3

Step-by-step explanation:

The base of a cylinder is a circle, so we need to calculate the area of the circle first. The equation for the area of a circle is:

area (a) = pi * r^2 =3.14*2*2 =12.56sq.inches

again,

volume of cylinder = area of the base * the height

= 12.56 * 7

= 87.92 inches cubed or 87.92 in.^3

5 0
3 years ago
Help please quick!!!!15 points!! What is the area of this parallelogram
Stells [14]

Answer:

132

Step-by-step explanation:

area of a parallelogram is b*h

(6+5)(12)=132

3 0
3 years ago
Match the expressions with their equivalent simplified expressions.
Tasya [4]

Answer:

\sqrt[4]{\frac{16x^6y^4}{81x^2y^8}}\rightarrow\frac{2x}{3y}\\\sqrt[4]{\frac{81x^2y^{10}}{81x^6y^6}} \rightarrow\frac{3y}{2x}\\\sqrt[3]{\frac{64x^8y^7}{125x^2y^{10}}}\rightarrow\frac{4x^2}{5y}\\\sqrt[5]{\frac{243x^{17}y^{16}}{32x^7y^{21}}}\rightarrow\frac{3x^2}{2y}\\\sqrt[5]{\frac{32x^{12}y^{15}}{243x^7y^{10}}} \rightarrow\frac{2xy}{3}\\\sqrt[4]{\frac{16x^{10}y^{9}}{256x^2y^{17}}}\rightarrow\frac{x}{2y}


Step-by-step explanation:

\sqrt[4]{\frac{16x^6y^4}{81x^2y^8}} =\sqrt[4]{\frac{(2^4)(x^{6-2})(y^{4-8})}{(3^4)}} =\sqrt[4]{\frac{2^4x^4y^{-4}}{3^4}} =\frac{2xy^{-1}}{3}=\frac{2x}{3y}

\sqrt[4]{\frac{81x^2y^{10}}{81x^6y^6}} =\sqrt[4]{\frac{(3^4)(x^{2-6})(y^{10-6})}{(2^4)}} =\sqrt[4]{\frac{3^4x^{-4}y^{4}}{2^4}} =\frac{3x^{-1}y^1}{3}=\frac{3y}{2x}

\sqrt[3]{\frac{64x^8y^7}{125x^2y^{10}}} =\sqrt[3]{\frac{(4^3)(x^{8-2})(y^{7-10})}{(5^3)}} =\sqrt[3]{\frac{4^3x^6y^{-3}}{5^3}} =\frac{4x^2y^{-1}}{5}=\frac{4x^2}{5y}

\sqrt[5]{\frac{243x^{17}y^{16}}{32x^7y^{21}}} =\sqrt[5]{\frac{(3^5)(x^{17-7})(y^{16-21})}{(2^5)}} =\sqrt[5]{\frac{3^5x^{10}y^{-5}}{2^5}} =\frac{3x^2y^{-1}}{2}=\frac{3x^2}{2y}

\sqrt[5]{\frac{32x^{12}y^{15}}{243x^7y^{10}}} =\sqrt[5]{\frac{(2^5)(x^{12-7})(y^{15-10})}{(3^5)}} =\sqrt[5]{\frac{2^5x^{5}y^{5}}{3^5}} =\frac{2x^1y^{1}}{3}=\frac{2xy}{3}

\sqrt[4]{\frac{16x^{10}y^{9}}{256x^2y^{17}}} =\sqrt[4]{\frac{(2^4)(x^{10-2})(y^{9-17})}{(4^4)}} =\sqrt[4]{\frac{2^4x^{8}y^{-8}}{4^4}} =\frac{2x^{1}y^{-1}}{4}=\frac{x}{2y}

Thus,

\sqrt[4]{\frac{16x^6y^4}{81x^2y^8}}\rightarrow\frac{2x}{3y}\\\sqrt[4]{\frac{81x^2y^{10}}{81x^6y^6}} \rightarrow\frac{3y}{2x}\\\sqrt[3]{\frac{64x^8y^7}{125x^2y^{10}}}\rightarrow\frac{4x^2}{5y}\\\sqrt[5]{\frac{243x^{17}y^{16}}{32x^7y^{21}}}\rightarrow\frac{3x^2}{2y}\\\sqrt[5]{\frac{32x^{12}y^{15}}{243x^7y^{10}}} \rightarrow\frac{2xy}{3}\\\sqrt[4]{\frac{16x^{10}y^{9}}{256x^2y^{17}}}\rightarrow\frac{x}{2y}

3 0
3 years ago
Help Would Be Appreciated!
ycow [4]

With an equation you must isolate x or whatever the variable is. Operations are the things used to make the difference like +,-,x,/.

A great example of this is the following

4x-12=0

First add 12 to both sides making the equation go to

4x=12

now divide 4 from both sides making

x=3


5 0
3 years ago
Read 2 more answers
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