2 years ago

Please help solving the attached image!

Mathematics

1 answer:

Triss [41]2 years ago

7 0

Answer:

6,780.00 is right answer try it

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For f(x) = -8x +8, find f(-3)

aniked [119]

Answer:

f(x)=-8x+8

f(-3)

ANSWER: 11/8

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3 years ago

Find the seventh term of the

jekas [21]

Answer:

$T_7 = \frac{64}{729}$

Step-by-step explanation:

Given

$a =1$

$r = \frac{2}{3}$

Required

Determine the 7th term

The nth term of a gp is:

$T_n = a * r^{n-1$

So, we have:

$T_7 = 1 * \frac{2}{3}^{7-1$

$T_7 = 1 * \frac{2}{3}^{6$

$T_7 = 1 * \frac{2^6}{3^6}$

$T_7 = 1 * \frac{64}{729}$

$T_7 = \frac{64}{729}$

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3 years ago

A point moves along the curve y = √ x in such a way that the y-component of the position of the point is increasing at a rate of

Eduardwww [97]

Answer:

The value of x component changes at a rate of $\frac{dx}{dt}=4\sqrt{x}$ units per second

Step-by-step explanation:

We are given that $y=x^{\frac{1}{2}}$

Differentiating on both sides with respect to time we get

$\frac{dy}{dt}=\frac{d\sqrt{x}}{dt}\\\\\frac{dy}{dt}=\frac{1}{2}x^{\frac{-1}{2}}(\frac{dx}{dt})\\\\\frac{dy}{dt}=\frac{1}{2\sqrt{x}}\frac{dx}{dt}$

It is given that $\frac{dy}{dt}=2units/sec$

Solving for $\frac{dx}{dt}$ we get

$\frac{dx}{dt}=\frac{dy}{dt}\times 2\sqrt{x}\\\\\frac{dx}{dt}=4\sqrt{x}$

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3 years ago

How do you find the radius of a circle with a circumference of 35π yards?

Tpy6a [65]

Answer:

r ≈ 5.57

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Have a blessed day

4 0

3 years ago

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allochka39001 [22]

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4 0

3 years ago

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