MN = √2
it comes from √(1^2 + 1^2) = √2 (use phytagoras)
LK = 2 x MN = 2 √2
NK = √(2^2 + 1^2) = √5
ML = NK = √5
so the perimeter
√2 + 2 √2 + √5 + √5
3 √2 + 2 √5
All scalar multiples of the vector [ 4, 5] makes the
line y = 5/4 x.
The matrix A of the orthogonal projection onto the line L is made of the
coordinates of the projections of the base trajectories i and j onto the line L
printed in columns.
The line L: y = 5/4*x
Orthogonal line passing over the point (1, 0): y = -4/5 *x + 4/5
Point of Intersection: (16/41, 21/41)
Projections: P(i) = 16/41 i + 21/41 j, P(j) = 16/41 i + 21/41 j
The matrix:
A = || 16/41..16/41||
......|| 16/41....16/41 ||
U see the X line ?
that made a line, which is = 180°
so 180 - 120 = 60
Angle A is 60°
mark me brainliest if i right ty
Answer:
15
Step-by-step explanation:
To subtract 2 1/2 - 1 3/5, first, you need a common denominator for the fractions, which is 10.
The subtraction becomes
2 5/10 - 1 6/10
Now you need to subtract 1 6/10 from 2 5/10.
Since the fraction part involves the subtraction 5/10 - 6/10, we need to borrow. You must change 2 5/10 to a mixed numeral with a larger numerator than 5, so you can subtract 6/210 from it.
Start with 2 5/10.
Borrow 1 from the 2. The 1 you borrow from 2 will be added to 5/10.
You think of the borrowed 1 as 10/10. Now you add 10/10 to 5/10.
2 5/10 becomes 1 15/10. Now that the fraction has a numerator grater than 6, you can do the subtraction.
2 5/10 - 1 6/10 =
= 1 15/10 - 1 6/10
Answer: 15
Answer:
7 1/17 shifts
Step-by-step explanation:
That would be 7 1/2 divided by 1 1/16
= 15/2 / 17/16
= 15/2 * 16/17
= 15 * 8 / 17
= 120/17
= 7 1/17 shifts