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svp [43]
3 years ago
11

I'll give you brainliest answer!! Help me. This diagram shows a smaller square inscribed within a larger square.

Mathematics
2 answers:
Veseljchak [2.6K]3 years ago
8 0
Each side of the smaller square is the hypotenuse of the triangles with legs of 3 and 4.  From the Pythagorean Theorem, we can calculate the hypotenuse:
hypotenuse^2 = 3^2 + 4^2
hypotenuse^2 = 9 + 16
hypotenuse^2 = 25
hypotenuse = 5
Therefore, the area of the smaller square is 5 * 5 = 25

olga55 [171]3 years ago
4 0
The answer would be 256 as the area because roughly the 4 closes in onto the smaller square which makes it 4 x 4 so what I would do is go first 4 x4 which equals 16 and then do it over 4 x 4 equals 16 once again so 16 x 16 equals 256 your welcome!!!!! :)
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Answer:

For x∈ {-∞,-3} y<0, below x-axis

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Step-by-step explanation:

f(x)=2x^{3}-26x-24

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2x^{3}-26x-24=0\\2x^{3}-2x-24x-24=0\\2x(x^{2} -1)-24(x+1)=0\\2x(x+1)(x-1)-24(x+1)=0\\(x+1)(2x^{2} -2x-24)=0\\=> x+1=0 => x_{1}=-1\\

=> 2x^{2} -2x-24=0\\=>2(x^{2} -x-12)=0\\=> x^{2} -x-12=0\\=> x^{2} -4x+3x-12=0\\=> x(x-4)+3(x-4)=0\\=> (x-4)(x+3)=0\\

=> x-4=0\\=> x_{2}=4\\=> x+3=0\\=>x_{3}=-3\\

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x∈ {-3,-1} y>0, above x-axis

x∈ {-1,4} y<0, below x-axis

x∈ {4,∞} y>0, above x-axis



7 0
3 years ago
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