Question

PLEASE HELP

Answer 1

Answer:

$12\sqrt{3}$ feet

Step-by-step explanation:

In a 30-60-90 triangle, the ratios of the side lengths of the triangle is $1:\sqrt{3} :2$

Where 1 is the shortest leg, root(3) is the longer leg, and 2 is the hypotenuse.

First we can set x equals to the length of the original pole, and so the shorter leg has a length of x/3 and using the ratio of side lengths, we can find that:

$\frac{x}{3} * \sqrt{3} = \frac{\sqrt{3} x}{3} = 12$

Solving for x, we find that

$x=\frac{36}{\sqrt{3} } = \frac{36 * \sqrt{3} }{\sqrt{3} * \sqrt{3} } = \frac{36 \sqrt{3} }{3} = 12\sqrt{3}$

So the length of the original pole would be $12\sqrt{3}$ feet

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