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trapecia [35]
3 years ago
14

PLEASE HELP

Mathematics
1 answer:
irina [24]3 years ago
6 0

Answer:

12\sqrt{3} feet

Step-by-step explanation:

In a 30-60-90 triangle, the ratios of the side lengths of the triangle is 1:\sqrt{3} :2

Where 1 is the shortest leg, root(3) is the longer leg, and 2 is the hypotenuse.

First we can set x equals to the length of the original pole, and so the shorter leg has a length of x/3 and using the ratio of side lengths, we can find that:

\frac{x}{3} * \sqrt{3} = \frac{\sqrt{3} x}{3} = 12

Solving for x, we find that

x=\frac{36}{\sqrt{3} } = \frac{36 * \sqrt{3} }{\sqrt{3} * \sqrt{3} } = \frac{36  \sqrt{3} }{3} = 12\sqrt{3}

So the length of the original pole would be 12\sqrt{3} feet

If you found this answer helpful, please consider marking it as brainliest, or give it a thanks and a 5 star review. Thanks!

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