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a_sh-v [17]
3 years ago
10

The coordinates of a quadrilateral are (1,3),(7-3),(1,-9) , and (-5,-3). What shape is formed? Select all that apply

Mathematics
2 answers:
LenKa [72]3 years ago
8 0

Answer:

Square

Step-by-step explanation:

There are different types of quadrilateral,

Kite  :  a quadrilateral which has two pairs of adjacent equal sides,

Rectangle : a quadrilateral which has two pairs of opposite equal sides and 4 right angles,

Rhombus  : a quadrilateral which has equal sides with two pairs of equal opposite angles,

Square : a quadrilateral which has equal sides with 4 right angles,

Trapezoid :  a quadrilateral which has one pairs of opposite parallel sides,

Let A≡(1,3), B≡(7,-3), C≡(1,-9) and D≡(-5,-3),

By Distance formula,

AB=\sqrt{(-3-3)^2+(7-1)^2}

=\sqrt{6^2+6^2}=\sqrt{72}=6\sqrt{2}\text{ unit}

Similarly,

BC=6\sqrt{2}\text{ unit}

CD=6\sqrt{2}\text{ unit}

DA=6\sqrt{2}\text{ unit}

Now, the slope of AB,

m_1=\frac{-3-3}{7-1}=\frac{-6}{6}=-1

Similarly,

The slope of BC,

m_2=1

Since, m_1\times m_2=-1

Hence, ∠B = 90°,

Similarly, We can obtain,

∠A = ∠C = ∠D = 90°

Therefore, By the above definitions it is clear that ABCD is a square.

pogonyaev3 years ago
6 0
Kite. The other answers don't fit the criteria.

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Sidana [21]
I’m pretty sure it’s x=10 because
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xenn [34]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

6z + 7  = 8z - 9

8z - 9 = 6z + 7

Add sides 9

8z - 9 + 9 = 6z + 7 + 9

8z = 6z + 16

Subtract sides 6z

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\frac{2z}{2}  =  \frac{16}{2}  \\

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Done...

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