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Vikentia [17]
3 years ago
9

In how many ways can a committee of three men and three women be formed from a group of eight men and seven women

Mathematics
1 answer:
azamat3 years ago
8 0
<h3>Answer:  1960 </h3>

==========================================================

Explanation:

Order doesn't matter when it comes to committees without rankings. Each person on the committee is of equal rank to anyone else. This means we'll use a combination instead of a permutation.

We have 8 men and 3 seats to fill for the men. Plug n = 8 and r = 3 into the nCr combination formula

n C r = (n!)/(r!(n-r)!)

8 C 3 = (8!)/(3!*(8-3)!)

8 C 3 = (8!)/(3!*5!)

8 C 3 = (8*7*6*5*4*3*2*1)/((3*2*1)*(5*4*3*2*1))

8 C 3 = (40320)/((6)*(120))

8 C 3 = (40320)/(720)

8 C 3 = 56

This means there are 56 ways to select the three men from a pool of eight.

Through similar steps, you should plug n = 7 and r = 3 into the nCr combination formula to get 7 C 3 = 35. This means there are 35 ways to pick the three women from a pool of seven.

Overall, there are 56*35 = 1960 ways to select the entire committee of 3 men and 3 women (from a pool of 8 men and 7 women).

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the number of diagonals that can be drawn in a opolygon of n sides is 1/2n(n-1)-n. If 230 diagonsaals can be drawn how many side
Vitek1552 [10]

Answer:

n = 20

Step-by-step explanation:

The number of diagonal that can be drawn in a polygon of n sides is given by :

D=\dfrac{n(n-3)}{2}

If the number of diagonals are 230, then put D = 230 in above formula. So,

230=\dfrac{n(n-3)}{2}\\\\460=n^2-3n\\\\n^2-3n-460=0

It is a quadratic equation, the value of n is equal to 20.

It means that for 230 diagonal, there are 20 sides of the polygon.

7 0
3 years ago
What is an integer in math ​
san4es73 [151]

Answer:

An integer is a whole number that is not a fraction.

8 0
3 years ago
Read 2 more answers
5^9 · 5^3 =<br><br> AH) 5^6<br> AH) 5^-6<br> AH) 5^12<br> AH) 5^3
Temka [501]

Answer:

5´12

Step-by-step explanation:

same base 5

9+3=12

5'12

5 0
3 years ago
A jug of orange juice is made by mixing 21 juice with 51 water how many litres of water will be needed for 61 of juice?​
sweet [91]

Answer:

Step-by-step explanation:

No there will be no need for 61 because you’ll be at max capacity

3 0
3 years ago
Celia has some cakes.
Vadim26 [7]

The carrot cakes are the fraction of the cake given by 1 - \frac{6}{7} multiplied by \frac{1}{3}

  • The fraction of the cakes that are carrot cakes is \underline {\dfrac{1}{21}}

<h3>How are the cakes evaluated as fractions?</h3>

The fraction of the cake that are chocolate cake = \dfrac{2}{3}

The fraction of the remaining cake that cheesecakes = \dfrac{6}{7}

The rest of the cakes = carrot cakes

Required:

The fraction of the cake that  are carrot cakes

Solution:

The fraction of the cakes that are not chocolate cake = 1 - \dfrac{2}{3} = \mathbf{ \dfrac{1}{3}}

The fraction of the remaining cakes that are cheesecake = \dfrac{6}{7} \times \dfrac{1}{3} = \mathbf{ \dfrac{6}{21}}

The fraction of the cake that are carrot cake = \dfrac{1}{3} - \dfrac{6}{7} \times \dfrac{1}{3} = \mathbf{\dfrac{1}{21}}

  • The fraction of the cakes that are carrot cake is \underline{\dfrac{1}{21}}

Learn more about fractions here:

brainly.com/question/3840488

5 0
2 years ago
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