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mixer [17]
2 years ago
5

-3/5b+7+2/5b=19 please answer

Mathematics
1 answer:
ikadub [295]2 years ago
7 0

Step-by-step explanation:

here your answer

above photo is your answer

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two friends went to a restaurant and ordered one plain pizza and two sodas. their bill totaled $15.95. later that day, five frie
oksano4ka [1.4K]
X= cost per pizza
y= cost per soda


1ST VISIT TO RESTAURANT
x + 2y= $15.95

2ND VISIT TO RESTAURANT
3x + 5y= $45.90


STEP 1
multiply equation from 1st visit by -3. Will be able to solve by elimination method in step 2.

-3(x + 2y)= -3(15.95)
multiply -3 by each term

(-3 * x) + (-3 * 2y)= (-3 * 15.95)

-3x - 6y= -47.85


STEP 2
add 2nd visit equation to new 1st
visit equation in step 1.

3x + 5y= 45.90
-3x - 6y= -47.85
x term will cancel out; solve for y

-y= -1.95
divide both sides by -1

y= $1.95 per soda


STEP 3
substitute y value in either original equation to solve for x

x + 2y= $15.95

x + (2 * 1.95)= 15.95
multiple in parentheses

x + 3.90= 15.95
subtract 3.90 from both sides

x= $12.05 per pizza


CHECK
3x + 5y= $45.90
3(12.05) + 5(1.95)= 45.90
36.15 + 9.75= 45.90
45.90= 45.90


ANSWER: Each pizza costs $12.05 and each soda costs $1.95.

Hope this helps! :)
4 0
3 years ago
Please help me! Send me picture of your work please. WORTH 10 POINTS!
Veseljchak [2.6K]
The answer is 74! But when u divide 2,665 by 36= 74. To check your answer it's 2,664 (36x74=2,664) That's means there has to been a remainder. Sorry not telling u the remainder
3 0
3 years ago
If the ratio is a:b=7:4 b:c=2:5 work out a:c=?
frozen [14]

Step-by-step explanation:

a:b=7:4 b:c=2:5

a:c = 7:5

6 0
2 years ago
HELP ME PLZ AND I WILL SHOW YOU MY KITTTTY
oksian1 [2.3K]
Welp looks like I won't be seeing that cat, darn it
6 0
3 years ago
Prove that if a and b are integers, then a^2-4b egal or non-egal 2
Lera25 [3.4K]

Answer:

tex]a^2 - 4b \neq 2[/tex]

Step-by-step explanation:

We are given that a and b are integers, then we need to show that a^2 - 4b \neq 2

Let  a^2 - 4b = 2

If a is an even integer, then it can be written as a = 2c, then,

a^2 - 4b = 2\\(2c)^2 - 4b =2\\4(c^2 -b) = 2\\(c^2 -b) =\frac{1}{2}

RHS is a fraction but LHS can never be a fraction, thus it is impossible.

If a is an odd integer, then it can be written as a = 2c+1, then,

a^2 - 4b = 2\\(2c+1)^2 - 4b =2\\4(c^2+c-b) = 2\\(c^2+c-b) =\frac{1}{4}

RHS is a fraction but LHS can never be a fraction, thus it is impossible.

Thus, our assumption was wrong and a^2 - 4b \neq 2.

7 0
3 years ago
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