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3 years ago

4. Write -4.83 as a mixed number. what is 8.3 in its simplest form

Mathematics

1 answer:

Black_prince [1.1K]3 years ago

4 0

Answer:

-4 83/100 8 3/10

Step-by-step explanation:

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Determine the measure of each segment then indicate whether the statements are true or false

kupik [55]

Answer:

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

Step-by-step explanation:

Considering the graph

Given the vertices of the segment AB

A(-4, 4)

B(2, 5)

Finding the length of AB using the formula

$d_{AB}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(2-\left(-4\right)\right)^2+\left(5-4\right)^2}$

$=\sqrt{\left(2+4\right)^2+\left(5-4\right)^2}$

$=\sqrt{6^2+1}$

$=\sqrt{36+1}$

$=\sqrt{37}$

$d_{AB}\:=\sqrt{37}$

$d_{AB}=6.08$ units

Given the vertices of the segment JK

J(2, 2)

K(7, 2)

From the graph, it is clear that the length of JK = 5 units

$d_{JK}=5$ units

Given the vertices of the segment GH

G(-5, -2)

H(-2, -2)

Finding the length of GH using the formula

$d_{GH}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(-2-\left(-5\right)\right)^2+\left(-2-\left(-2\right)\right)^2}$

$=\sqrt{\left(5-2\right)^2+\left(2-2\right)^2}$

$=\sqrt{3^2+0}$

$=\sqrt{3^2}$

$\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

$d_{GH}\:=\:3$ units

Thus, from the calculations, it is clear that:

$d_{AB}=6.08$

$d_{JK}=5$

$d_{GH}\:=\:3$

Thus,

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

8 0

3 years ago

Help! i need an answer as soon as possible!

kupik [55]

Answer:

x = 0, 2, -3

Step-by-step explanation:

these are the points from the function f(x) that we are certain that the y value is -1. if you look at the graph at each of these induvidual points y is -1

8 0

3 years ago

You missed an A in your art course by only 7 points. Your point total for the course was 371. How many points were possible in t

Nikitich [7]

The number of points that were possible in the course is 420

What is the required number of points for grade A?

The number of points the student needs to have to make grade A is the student's current points of 371 plus the 7 points remaining to make grade A

Total points for A=371+7

total points for grade A=378

90% of the course total=378

divide both sides 90

90% /90 =378/90

1%=378/90

100%=378/90*100

100%=420

Find out more about course points on:brainly.com/question/8429607

#SPJ1

3 0

2 years ago

<img src="https://tex.z-dn.net/?f=make%20x%20the%20subject%20of%20formula%20in%20the%20equation%204a%5Csqrt%7Bx%7D%20%3D%5Cfrac%

kipiarov [429]

Answer: $x = (\frac{1}{4ab})^{2}$

Step-by-step explanation:

Given:

$4a\sqrt{x} = \frac{1}{b}$

To make $x$ the subject of the formula means that we want to make $x$ to stand alone , the first thing to do is to multiply through by 1/4a , that is