Given
mean of 406 grams and a standard deviation of 27 grams.
Find
The heaviest 14% of fruits weigh more than how many grams?
Explanation
given
mean = 406 gms
standard deviation = 27 gms
using standard normal table ,
![\begin{gathered} P(Z>z)=14\% \\ 1-P(Zso , [tex]\begin{gathered} x=z\times\sigma+\mu \\ x=1.08\times27+406 \\ x=435.16 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20P%28Z%3Ez%29%3D14%5C%25%20%5C%5C%201-P%28Zso%20%2C%20%5Btex%5D%5Cbegin%7Bgathered%7D%20x%3Dz%5Ctimes%5Csigma%2B%5Cmu%20%5C%5C%20x%3D1.08%5Ctimes27%2B406%20%5C%5C%20x%3D435.16%20%5Cend%7Bgathered%7D)
Final Answer
Therefore , The heaviest 14% of fruits weigh more than 435.16 gms
Answer:
the solution is the whole line y = -x + 7
Step-by-step explanation:
both equations are identical
2y = 14 - 2x
=> y = 7 - x
which is exactly the same information as y=-x+7
so, there is no single crossing point. they are exactly covering each other. what "remains" is simply the whole line.
$2.10 - $2 = $0.10
The banana cost 10 cents.
Obviously, there is 784/7, but there is a less common kind of expression that also works. Since a fraction is similar to a division expression, you can flip 7 to make 1/7. The other expression could be 1/7 x 784.
So the two expressions could be 784/7 and 1/7 x 784
---
hope it helps
The answer is 500 m.
d = u * t + 1/2 a * t²
We know:
d = ? (distance)
u = 0 (the initial velocity)
t = 10 s (time
a = 10 m/s² (acceleration
d = u * t + 1/2 a * t²
d = 0 * 10 + 1/2 * 10 * 10²
d = 0 + 1/2 * 10 * 100
d = 500 m
