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GREYUIT [131]
2 years ago
8

(Classify the segment) Math Help Quick Please!

Mathematics
2 answers:
aev [14]2 years ago
4 0

Answer:

(a) Altitude

(b) perpendicular bisector

(c) median

Step-by-step explanation:

  • The perpendicular bisector of a side of a triangle is a line <u>perpendicular </u>to the side and passing through its midpoint.
  • The angle bisector of an angle of a triangle is a straight line that <u>divides the angle</u> into t<u>wo congruent angles</u>.
  • A median of a triangle is a line segment drawn <u>from a vertex</u> to the <u>midpoint</u> of the opposite side of the vertex.
  • An altitude of a triangle is the <u>perpendicular</u> segment <u>from a vertex</u> of a triangle <u>to the opposite side</u> (or the line containing the opposite side).

(a) Altitude

m∠KML = 90° but JM ≠ ML (so not perpendicular bisector)

(b) perpendicular bisector

AD = DB and m∠BDE = 90°

(c) median

QS = QR  ⇒  S is the midpoint QR, BUT it is not perpendicular to QR, so median

Aleonysh [2.5K]2 years ago
4 0
<h3>#a</h3>

  • <em>Perpendicular</em><em> </em><em>bisector</em><em> </em><em>of</em><em> </em><em>\overline {JL}</em>
  • <em>Angle</em><em> </em><em>bisector</em><em> </em><em>of</em><em> </em><em>∠</em><em>K</em>
  • <em>Median</em><em> </em><em>of</em><em> </em><em>△</em><em>JKL</em>
  • <em>Altitude</em><em> </em><em>of</em><em> </em><em>△</em><em>JKL</em>

\red{ \rule{35pt}{2pt}} \orange{ \rule{35pt}{2pt}} \color{yellow}{ \rule{35pt} {2pt}} \green{ \rule{35pt} {2pt}} \blue{ \rule{35pt} {2pt}} \purple{ \rule{35pt} {2pt}}

<h3>#b</h3>

  • <em>None</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>above</em>

\red{ \rule{35pt}{2pt}} \orange{ \rule{35pt}{2pt}} \color{yellow}{ \rule{35pt} {2pt}} \green{ \rule{35pt} {2pt}} \blue{ \rule{35pt} {2pt}} \purple{ \rule{35pt} {2pt}}

<h3>#c</h3>

  • <em>Perpendicular bisector of \overline {QR}</em>
  • <em>}[/tex]Angle bisector of ∠</em><em>P</em>
  • <em>Median of △</em><em>PQR</em>
  • <em>Altitude of △</em><em>PQR</em>
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