Answer:
B
Step-by-step explanation:
All you have to basically do on this one is go backwards.
The beginning equation is 4x+4=12, so to first revesre the adding we are going to use 12, the product, and subtract 4 from it (since that is what was added).
12-4=8
Now you need to reverse the times 4, so to do that just divide instead because that is the invese of multiplication.
8/4=2
Now you have 2, which is the variable, x. To make sure this is right you can just put it into the equation and see if 4x2+4 is 12
Hope this helped!
Answer:
y = (11x + 13)e^(-4x-4)
Step-by-step explanation:
Given y'' + 8y' + 16 = 0
The auxiliary equation to the differential equation is:
m² + 8m + 16 = 0
Factorizing this, we have
(m + 4)² = 0
m = -4 twice
The complimentary solution is
y_c = (C1 + C2x)e^(-4x)
Using the initial conditions
y(-1) = 2
2 = (C1 -C2) e^4
C1 - C2 = 2e^(-4).................................(1)
y'(-1) = 3
y'_c = -4(C1 + C2x)e^(-4x) + C2e^(-4x)
3 = -4(C1 - C2)e^4 + C2e^4
-4C1 + 5C2 = 3e^(-4)..............................(2)
Solving (1) and (2) simultaneously, we have
From (1)
C1 = 2e^(-4) + C2
Using this in (2)
-4[2e^(-4) + C2] + 5C2 = 3e^(-4)
C2 = 11e^(-4)
C1 = 2e^(-4) + 11e^(-4)
= 13e^(-4)
The general solution is now
y = [13e^(-4) + 11xe^(-4)]e^(-4x)
= (11x + 13)e^(-4x-4)
Example 250
word form:
two hundred and fifty
expanded form:
2+5+0
standard form:
250
Answer:
1/25 of a mile per minute, I think
Step-by-step explanation:
