Width =3.5, length = 4
Let's make a few equations to summarize what we know.:
a = 14
l = 2w -3
a = wl
Now let's substitute the expression for l into the expression for area and solve.
a = w(2w - 3)
a = 2w^2 - 3w
14 = 2w^2 - 3w
0 = 2w^2 - 3w - 14
which factors into
(2w - 7) (w + 2)
Solving for w
2w - 7 = 0
2w = 7
w = 3.5
w+2 = 0
w = -2
So w can be either 3.5 or -2. Since a negative width doesn't make sense, w = 3.5
Let's verify
w = 3.5
l = 2w - 3
l = 2*3.5 - 3
l = 7 - 3
l = 4
a = wl
a = 3.5 * 4
a = 14
So the width is 3.5 and the length is 4.
Answer:
pi*2^2*2sqrt3/3
if pi=3
8sqrt3
Step-by-step explanation:
Answer:
I think i wanna say one of the fractions
Step-by-step explanation:
What exactly are you asking. Are you asking for area or perimeter?
