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3 years ago

3. Casey wants to do some baking. She has 6 cups of flour. One of the recipes she wants

Mathematics

1 answer:

Juliette [100K]3 years ago

6 0

Step-by-step explanation:

assuming cup of flower means 1 cup of flower

3+2+1=6

She has enough to make the three recipes and she has nothing left over

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When planning a date night, you have a choice of 2 types of restaurants: pizza (P) or barbeque (B); a choice of 3 types of movie

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Answer:

$S = \{PRC, PRI,PAC,PAI,PDC,PDI,BRC, BRI,BAC,BAI,BDC,BDI\}$

Step-by-step explanation:

Given

$Restaurant = \{P,B\}$

$Movies = \{R,A,D\}$

$Post-movie = \{C,I\}$

Required

List out the sample space

To do this, we simply pick 1 item in each category, without repetition.

So, we have:

$S = \{PRC, PRI,PAC,PAI,PDC,PDI,BRC, BRI,BAC,BAI,BDC,BDI\}$

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3 years ago

WILL GIVE BRAINLIEST& 15 PTS.

kicyunya [14]

Answer:

The given fraction $\frac{x^3-x^2}{x^3}$ reduces to $\frac{x-1}{x}$

Step-by-step explanation:

Consider the given fraction $\frac{x^3-x^2}{x^3}$

We have to reduce the fraction to the lowest terms.

Consider numerator $x^3-x^2$

We can take x² common from both the term,

Thus, numerator can be written as $x^2(x-1)$

Given expression can be rewritten as ,

$\frac{x^3-x^2}{x^3}=\frac{x^2(x-1)}{x^3}$

We can now cancel $x^2$ from both numerator and denominator,

$\Rightarrow \frac{x^2(x-1)}{x^3}=\frac{x^2(x-1)}{x^2 \cdot x}$

$\Rightarrow \frac{(x-1)}{x^2 \cdot x}=\frac{x-1}{x}$

Thus, the given fraction $\frac{x^3-x^2}{x^3}$ reduces to $\frac{x-1}{x}$

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3 years ago

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Answer:

3/9

Step-by-step explanation:

3/9 = 0.33333333

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3 years ago

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Hunter-Best [27]

Answer:

2/1

Step-by-step explanation:

20/10 devided by 10 to both numbers

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3 years ago

Sebastian used the table and correctly identified that the data does not represent a logarithmic function. What information did

Lelechka [254]

Answer:

D. The table shows two x-intercepts and it changes from increasing to decreasing.

Step-by-step explanation:

A logarithmic function isn't either of these. This is the correct answer of ed-genuity. Hope this helped! :)

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4 years ago

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