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Trava [24]
3 years ago
13

3. Casey wants to do some baking. She has 6 cups of flour. One of the recipes she wants

Mathematics
1 answer:
Juliette [100K]3 years ago
6 0

Step-by-step explanation:

assuming cup of flower means 1 cup of flower

3+2+1=6

She has enough to make the three recipes and she has nothing left over

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12,000 g____1.2 kg A greater than B less than C equal to
serious [3.7K]
12000 g would be equal to 12 kg not 1.2 kg so the answer has to be A) greater than.

Answer: A) GREATER THAN
7 0
3 years ago
The interior angles formed by the sides of a quadrilateral have measures that sum to 360°.
vova2212 [387]

add all the angles and make them equal to 360

88 + 108 + (3x-6) + 2x = 360

196 + 5x -6 = 360

190 + 5x = 360

5x = 170

x = 34 = answer

4 0
3 years ago
2/7 divided by 6, fastest answer (and correct) gets brainest.
laiz [17]

Answer:

0.047619

P.S. do you need to round?

3 0
3 years ago
Read 2 more answers
What is the sum of the infinite geometric series? Sigma-Summation Underscript n = 1 Overscript 4 EndScripts (negative 144) (one-
Irina18 [472]

The sum of the infinite geometric series is -288.

<h2>Given that</h2>

A finite geometric series with n = 4, a₁ = -144, and r = ½.

<h3>We have to determine</h3>

What is the sum of the infinite geometric series?

<h3>According to the question</h3>

The sum of the infinite is determined by the following formula;

\rm S\infty = \dfrac{a_1(1-r^n)}{1-r}\\\\

A finite geometric series with n = 4, a₁ = -144, and r = ½.

Substitute all the values in the formula;

\rm S\infty = \dfrac{a_1(1-r^n)}{1-r}\\\\S\infty = \dfrac{-144 (1- \dfrac{1}{2}^4)}{1-\dfrac{1}{2}}\\\\S \infty = \dfrac{-144 \times \dfrac{15}{16}}{\dfrac{1}{2}}\\\\S \infty = -270

Therefore,

The sum of the infinite geometric series is,

\rm S = \dfrac{a_1}{1-r}\\\\S=\dfrac{-144}{1-\dfrac{1}{2}}\\\\S = \dfrac{-144}{0.5}\\\\S = -288

Hence, the sum of the infinite geometric series is -288.

To know more about Geometric Series click the link given below.

brainly.com/question/16037289

5 0
2 years ago
Help!!!!!!!!!!!!!!!!
valkas [14]
Under box 36x + 9, Drag the following:

A.) 9(4x + 1)
D.) (9 . 4x) + (9 . 1)

Under box 9(4x - 1), Drag the following:
B.) (3 . 12x) - (3 . 3)
C.) 36x - 9

Under box (4 . 9x) + (4 . 2), Drag the following:
E.) 4(9x + 2)
F.) 36x + 8

Hope this helps!
5 0
3 years ago
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