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Kitty [74]
3 years ago
12

???????????????????????

Mathematics
2 answers:
max2010maxim [7]3 years ago
8 0

Answer:

53

Step-by-step explanation:

Using SOHCAHTOA you already know all three side lengths so you could use sine, cosine, or tangent. I'll solve using sine:

sinB=\frac{4}{5}

Use the inverse of sin to isolate Angle B:

arcsin(sinB)=arcsin(\frac{4}{5} )

B=arcsin(\frac{4}{5} )

B=53 when rounded to the nearest degree

Firlakuza [10]3 years ago
3 0

Answer:

m∠B≈53°

Step-by-step explanation:

Since this is a 3, 4, 5 triangle, the angle measures are:

∠A=36.87°

∠B=53.13°

∠C=90°

m∠B≈53°

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Sedbober [7]
The slope is -1/2. I know this because slope intercept of a line is y = mx + b. In the equation, y = -1/2 + 1/4, the slope is -1/2 and the y intercept is 1/4.

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6 0
4 years ago
- Write a recursive formula to represent the sequence below.<br> (3,7, 11, 15, 19,23,27,31,35, ...)
NemiM [27]

<em><u>The recursive formula to find nth term of sequence is:</u></em>

a_n = 4n - 1 \text{ where } n \geq 1 and n  = 1, 2, 3, ....

<em><u>Solution:</u></em>

Given a sequence is:

3, 7, 11, 15, 19, 23, 27, 31, 35

<em><u>Let us find the difference between terms</u></em>

7 - 3 = 4

11 - 7 = 4

15 - 11 = 4

19 - 15 = 4

23 - 19 = 4

27 - 23 = 4

31 - 27 = 4

35 - 31 = 4

Thus the difference between terms is constant

Thus the given sequence is arithmetic sequence

An arithmetic sequence is a sequence of numbers such that the difference of any two successive members of the sequence is a constant

<em><u>The nth term of arithmetic sequence is given by:</u></em>

a_n =a_1+(n-1)d

a_n = the nᵗʰ term in the sequence

a_1 = the first term in the sequence

d = the common difference between terms

Here in the given sequence

d = 4

a_1=3

Substitute in above formula,

a_n = 3 + (n-1)(4)\\\\a_n = 3 + 4n - 4\\\\a_n = 4n - 1

<em><u>Thus the recursive formula to find nth term of sequence is:</u></em>

a_n = 4n - 1 \text{ where } n \geq 1 and n = 1, 2, 3, ......

8 0
3 years ago
What is the integral of ln(sqrt t)/t?
Alina [70]
<span> ∫ [ln(√t) / t] dx
let √t = u
t= u² → dx = 2u du
substitute in the integral
∫ [ln(√t) / t] dx = ∫ (ln u / u²) 2u du = ∫ (ln u / u²) 2u du = 2 ∫ (ln u / u) du
let ln u = x → d (ln u) = dx→ (1/u)du = dx
substituting again
2 ∫ (ln u / u) du = 2 ∫ x dx= 2 x²/ 2 = x² + c which,
substituting ln² u + c
as of the first substitution ln²(√t) + c
it concludes that
∫ [ln(√t) / t] dx = ln²(√t) + c
hope it helps
</span>
8 0
4 years ago
Ten students share 9 candy bars equally. what fraction of a candy bars does each student get
Solnce55 [7]
I think the answer is 0.9
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ASHA 777 [7]

Answer:

True

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4 years ago
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