Question

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Answer 1

Answer:

53

Step-by-step explanation:

Using SOHCAHTOA you already know all three side lengths so you could use sine, cosine, or tangent. I'll solve using sine:

$sinB=\frac{4}{5}$

Use the inverse of sin to isolate Angle B:

$arcsin(sinB)=arcsin(\frac{4}{5} )$

$B=arcsin(\frac{4}{5} )$

$B=53$ when rounded to the nearest degree

Answer 2

Answer:

m∠B≈53°

Step-by-step explanation:

Since this is a 3, 4, 5 triangle, the angle measures are:

∠A=36.87°

∠B=53.13°

∠C=90°

m∠B≈53°