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Artemon [7]
3 years ago
9

(05.01; 05.02 MC)

Mathematics
1 answer:
polet [3.4K]3 years ago
4 0

Answer: 4/9

Step-by-step explanation: we are going to multiply side to bottom so that would be 2/3x3 which equals 6/9 then you multiply  the multiplication ( 6/9) by the 2/3 which equals 12/27.  the GCF of 12 and 27 is 3. so when you simplify you get 4/9. mark me brainiliest  pls

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A square photograph is printed on a larger rectangular sheet of paper leaving a border around the
victus00 [196]

Answer:

E. x² + 11x - 42 = 0

Step-by-step explanation:

let the square sides be x

A = bh = (x + 3 + 3)(x + 2 + 3) = 72

(x + 6)(x + 5) = 72

x² + 11x + 30 = 72

x² + 11x - 42 = 0

4 0
3 years ago
If you start at 6:45 and end at 3:28 how long is it between
lora16 [44]
Your elapsed time is 8 hours and 53 minutes.
6 0
3 years ago
About 13​% of the population of a large country is nervous around strangersnervous around strangers. If two people are randomly​
Molodets [167]

Answer:

1.69% probability both are nervous around strangers.

24.31% probability at least one is nervous around strangers.

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they are nervous around strangers, or they are not. The people are chosen randomly, which means that the probability of a person being nervous around strangers is independent from other people. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

About 13​% of the population of a large country is nervous around strangers.

This means that p = 0.13.

Two people are randomly​ selected

This means that n = 2.

What is the probability both are nervous around strangers?

This is P(X = 2)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.13)^{2}.(0.87)^{0} = 0.0169

1.69% probability both are nervous around strangers.

What is the probability at least one is nervous around strangersnervous around strangers?

This is P(X \geq 1)

P(X \geq 1) = P(X = 1) + P(X = 2)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{2,1}.(0.13)^{1}.(0.87)^{1} = 0.2262

P(X = 2) = C_{2,2}.(0.13)^{2}.(0.87)^{0} = 0.0169

P(X \geq 1) = P(X = 1) + P(X = 2) = 0.2262 + 0.0169 = 0.2431

24.31% probability at least one is nervous around strangers.

3 0
3 years ago
Help me QUICK, plz! 15 points!
Anna007 [38]

Answer:

t=8

Step-by-step explanation:

Subtract 12t from both sides

(12t-12t) + 16 = (13t-12t) + 24

16 = 1t (or just t) + 24

Then subtract 16 from both sides, and bring "t" over the equals sign making it a negative integer.

-t = 8

t = 8

4 0
4 years ago
HURRY ILL GIVE YOU BRAINLIEST!! Select the correct answer.
Artist 52 [7]

Answer:

c

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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