Answer:
sorry I can't help you this is hard for me sorry. :(
Step-by-step explanation:
Answer:
The roots are not real.
Step-by-step explanation:
To prove : The roots of I/2 +9 (1-k) are real for all real values of k ?Solution :
The roots are real when discriminant is greater than equal to zero.
i.e b2-4ac>0 But the roots are imaginary therefore the roots of the given equation are not real for any value of k.If x²+kx+k=0, find the value of k, If the roots are real & equal.
Answer:
P [ X ≤ 9.8 ] = 0.1335
Step-by-step explanation:
P [ X ≤ 9.8 ] = [ ( 9.8 - 10.2 )/1.8√25 ]
P [ X ≤ 9.8 ] = - 0.4*5/1.8
P [ X ≤ 9.8 ] = - 2 / 1.8
P [ X ≤ 9.8 ] = - 1.11
From z- table we get: α = 0.1335
P [ X ≤ 9.8 ] = 0.1335 or P [ X ≤ 9.8 ] = 0.1335
Answer:
1. y=-5x+5
2. y=3x
3. the slope is 6 and the y-intercept is 7
Step-by-step explanation:
For this case we must solve the following equation:

We apply distributive property on the right side of the equation:

We subtract 6y on both sides of the equation:

We subtract 6 from both sides of the equation:

Dividing by 6 on both sides of the equation:

So, the result is 
Answer:
