All categories

3 years ago

Figure out the answer to this question.

Mathematics

2 answers:

pickupchik [31]3 years ago

8 0

5x-3y=9--(1)
4x-2y=12=>2x-y=6--(2)

Doing eq(2)×3

$\\ \tt\hookrightarrow 6x-3y=18$

Subtracting from eq(1)

$\\ \tt\hookrightarrow -x=-9$

$\\ \tt\hookrightarrow x=9$

Put in eq(2)

$\\ \tt\hookrightarrow 2(9)-y=6$

$\\ \tt\hookrightarrow y=12$

frutty [35]3 years ago

3 0

Answer:

(9, 12)

Step-by-step explanation:

Given system:

5x - 3y = 9
4x - 2y = 12

Solve by elimination, multiply the second equation by - 3/2 and add with the first one:

5x - 3y - 6x + 3y = 9 - 18
- x = - 9
x = 9

Find y:

5*9 - 3y = 9
45 - 3y = 9
3y = 45 - 9
3y = 36
y = 12

You might be interested in

The formula for a volume of a cylinder is V= pi r squared h/3. solve the equation for h, or height. PLZ help ASAP

Diano4ka-milaya [45]

Answer:

h=3V/πr²

Step-by-step explanation:

V= πr²h/3
πr²h=3V
h=3V/πr²

8 0

3 years ago

Read 2 more answers

Which equation has only one solution?

sveticcg [70]

A because only 6-5 = -1

7 0

3 years ago

Allison had 18 postage stamps she gave 2/9 of the stamps to her mother and used 1/2 of the remaining stamps to send letters to h

Travka [436]

So first you have to do 18 multiply by 2/9. This gets you 4, next you multiply by 1/2. This gets you 2.

ANSWER: She will have 2 stamps left.

5 0

3 years ago

Read 2 more answers

Robin can bake 140 cupcakes in 5 hours.

Advocard [28]

Answer:

28.

Step-by-step explanation:

28 x 5 = 140

140 divided by 28 = 5.

5 hours.. 140 cupcakes. You divide the amount by the hours, showing you that 28 cupcakes per hour is the answer.

5 0

3 years ago

Read 2 more answers

On #10 i need help to solve this. please and thank you.

valina [46]

10a. $f(x) = x - 4$
 $h(x) = \sqrt{x - 5}$
 $(f - h)(6) = (6 - 4) - (\sqrt{6 - 5})$
 $(f - h)(6) = 2 - \sqrt{1}$
 $(f - h)(6) = 2 - 1$
 $(f - h)(6) = 1$

10b. $f(x) = x - 4$
 $g(x) = \frac{1}{x - 3}$
 $(f * g)(x) = (x - 4)(\frac{1}{x - 3})$
 $(f * g)(x) = \frac{x - 4}{x - 3}$
 Domain: (-∞, 3) ∨ (3, ∞) {x|x ≠ 3}
 Interval Notation: (3 < x < 3), (3 > x > 3)

10c. $g(x) = \frac{1}{x - 3}$
 $h(x) = \sqrt{x - 5}$
 $(g * h)(x) = (\frac{1}{x - 3})(\sqrt{x - 5})$
 $(g * h)(x) = \frac{\sqrt{x - 5}}{x - 3}$

10d. $f(x) = x - 4$
 $g(x) = \frac{1}{x - 3}$
 $h(x) = \sqrt[3]{x - 7}$
 $h(x) = (f * g)(x)$
 $\sqrt[3]{x - 7} = (x - 4)(\frac{1}{x - 3})$
 $\sqrt[3]{x - 7} = \frac{x - 4}{x - 3}$
 $(\sqrt[3]{x - 7})^{3} = (\frac{x - 4}{x - 3})^{3}$
 $x - 7 = \frac{(x - 4)^{3}}{(x - 3)^{3}}$
 $(x - 3)^{3}(x - 7) = (x - 4)^{3}$
 $(x^{3} - 9x^2 + 27x + 27)(x - 7) = (x^{3} - 12x^{2} + 48x - 64)$
 $x^{4} - 16x^{3} + 90x^{2} - 216x + 189 = x^{3} - 12x^{2} + 48x - 64$
 $x^{4} + 90x^{2} - 216x + 189 = 17x^{3} - 12x^{2} + 48x - 64$
 $x^{4} + 102x^{2} - 216x + 189 = 17x^{3} + 48x - 64$
 $x^{4} + 102x^{2} + 189 = 17x^{3} + 264x - 64$
 $x^{4} + 102x^{2} + 253 = 17x^{3} + 264x$
 $x^{4} - 17x^{3} + 102x^{2} - 264x + 253 = 0$
 $x = 4\ or\ 8$

4 0

3 years ago