Question

Figure out the answer to this question.

Answer 1

• 5x-3y=9--(1)
• 4x-2y=12=>2x-y=6--(2)

Doing eq(2)×3

$\\ \tt\hookrightarrow 6x-3y=18$

Subtracting from eq(1)

$\\ \tt\hookrightarrow -x=-9$

$\\ \tt\hookrightarrow x=9$

Put in eq(2)

$\\ \tt\hookrightarrow 2(9)-y=6$

$\\ \tt\hookrightarrow y=12$

Answer 2

Answer:

• (9, 12)

Step-by-step explanation:

Given system:

• 5x - 3y = 9
• 4x - 2y = 12

Solve by elimination, multiply the second equation by - 3/2 and add with the first one:

• 5x - 3y - 6x + 3y = 9 - 18
• - x = - 9
• x = 9

Find y:

• 5*9 - 3y = 9
• 45 - 3y = 9
• 3y = 45 - 9
• 3y = 36
• y = 12