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3 years ago

HELP!!! HELPPP!!!

Mathematics

1 answer:

mihalych1998 [28]3 years ago

7 0

Answer:

22.75

I did some work to try and find this answer sorry if it is wrong I tried.

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Compare -5.5 and -26/5

Sveta_85 [38]

-26/5 is the larger number. It is -5.1.

4 0

2 years ago

Azarai is looking to purchase a new pair of basketball shorts costing $40. The New Jersey state tax rate is 7.5 percent. What fi

ratelena [41]

Answer:

$43.00

Step-by-step explanation:

final price = marked price + tax

= marked price + (tax rate) · (marked price)

= (marked pric) · (1 + tax rate)

= $40.00 · 1.075

= $43.00

7 0

3 years ago

Identify the expression with nonnegative limit values. More info on the pic. PLEASE HELP.

marshall27 [118]

Answer:

$\lim _{x\to 2}\:\frac{x-2}{x^2-2}\\\\ \lim _{x\to 11}\:\frac{x^2+6x-187}{x^2+3x-154}\\\\ \lim _{x\to \frac{5}{2}}\left\frac{2x^2+x-15}{2x-5}\right$

Step-by-step explanation:

a) $\lim _{x\to 3}\:\frac{x^2-10x+21}{x^2+4x-21}=\lim \:_{x\to \:3}\:\frac{\left(x-7\right)\left(x-3\right)}{\left(x+7\right)\left(x-3\right)}=\lim \:_{x\to \:3}\:\frac{x-7}{x+7}=\frac{3-7}{3+7}=-\frac{4}{10}=-\frac{2}{5}$

b) $\lim _{x\to -\frac{3}{2}}\left(\frac{2x^2-5x-12}{2x+3}\right)=\lim \:_{x\to -\frac{3}{2}}\:\frac{\left(2x+3\right)\left(x-4\right)}{\left(2x+3\right)}=\lim \:\:_{x\to \:-\frac{3}{2}}\:\left(x-4\right)=-\frac{3}{2}-4\\ \\ \lim _{x\to -\frac{3}{2}}\left(\frac{2x^2-5x-12}{2x+3}\right)=-\frac{11}{2}$

c) $\lim _{x\to 2}\:\frac{x-2}{x^2-2}=\frac{2-2}{\left(2\right)^2-2}=\frac{0}{4-2}=0$

d) $\lim _{x\to 11}\:\frac{x^2+6x-187}{x^2+3x-154}=\lim _{x\to 11}\:\frac{\left(x-11\right)\left(x+17\right)}{\left(x-11\right)\left(x+14\right)}=\lim _{x\to 11}\:\frac{\left(x+17\right)}{\left(x+14\right)}=\frac{11+17}{11+14}=\frac{28}{25}$

e) $\lim _{x\to 3}\:\frac{x^2-8x+15}{x-3}=\lim \:_{x\to \:3}\:\frac{\left(x-3\right)\left(x-5\right)}{x-3}=\lim _{x\to 3}\left(x-5\right)=3-5=-2$

f) $\lim _{x\to \frac{5}{2}}\left(\frac{2x^2+x-15}{2x-5}\right)=\lim \:_{x\to \:\frac{5}{2}}\frac{\left(2x-5\right)\left(x+3\right)}{2x-5}=\lim \:\:_{x\to \:\:\frac{5}{2}}\left(x+3\right)=\frac{5}{2}+3=\frac{11}{2}$

4 0

3 years ago

The admission fee at a water park is $12.50 for children and $25.00 for adults On a certain day 352 people entered the park and

N76 [4]

Answer:

Children = 137

Adults = 215

Step-by-step explanation:

The admission fee at a water park is $12.50 for children

and $25.00 for adults.

On a certain day, 352 people entered the park and the admission fees collected totalled $6,687.50

Let the number of children admitted be x ,

and the number of adults admitted be y.

This forms a simultaneous equation:

x + y = 352 ... (i)

$12.50x + $25.00y = $6,687.50 ... (ii)

Multiplyng (i) by 12.50 and (ii) by 1 we get;

12.5x + 12.5y = 4400 ... (i)

12.5x + 25y = 6,687.5 ... (ii)

Subtracting (ii) - (i) we get;

12.5y = 2687.5

y = 215

So the number of adults admitted = 215

And the number of children admitted = 352 - 215 = 137

6 0

3 years ago

Sin 90 +cos 50 -tan1

Feliz [49]

Answer:

1.62533254

Step-by-step explanation:

7 0

3 years ago