Answer:
The range is [-11, ∞).
Step-by-step explanation:
f(x)=3x^2+6x-8
This is a parabola which opens upwards.
Convert to vertex form:
= 3(x^2 + 2x) - 8
= 3 [ (x + 1)^2 - 1] - 8
= 3(x + 1)^2 - 3 - 8
= 3(x + 1)^2 - 11.
The minimum value is -11 so the range is [-11, ∞).
Step-by-step explanation:
What must be subtracted from each term of the ratio 3:7 so that the ratio becomes 2:5?
My attempt: Let two numbers be 3x and 7x. So, 3x−y7x−y=25⟹15x−5y=14x−2y⟹y=x3. But the answer is given as 13 only.
I wish somebody could provide some clarifications.
5^2 + x^2=8^2
25+x^2=64
X=6.2