The proportion of left-handed people in the general population is about 0.1. Suppose a random sample of 225 people is observed.
1. What is the sampling distribution of the sample proportion (p-hat)? In other words, what can we say about the behavior of the different possible values of the sample proportion that we can get when we take such a sample?
(Note: normal approximation is valid because .1(225) = 22.5 and .9(225) = 202.5 are both more than 10.)
2. Since the sample proportion has a normal distribution, its values follow the Standard Deviation Rule. What interval is almost certain (probability .997) to contain the sample proportion of left-handed people?
3. In a sample of 225 people, would it be unusual to find that 40 people in the sample are left-handed?
4. Find the approximate probability of at least 27 in 225 (proportion .12) being left-handed. In other words, what is P(p-hat ? 0.12)?
Guidance: Note that 0.12 is exactly 1 standard deviation (0.02) above the mean (0.1). Now use the Standard Deviation Rule.
-7,14,-28,<u>5</u><u>6</u><u>,</u><u>-</u><u>1</u><u>1</u><u>2</u>
an = a1(r)^n-1
a4 = -7(-2)^4-1
a4 = -7(-2)³
a4 = -7(-8)
a4 = 56
an = a1(r)^n-1
a5 = -7(-2)^5-1
a5 = -7(-2)⁴
a5 = -7(16)
a5 = -112
<h2>#CarryOnLearning</h2>
Answer:
C - The failure was a starting point for a buildup of aggression around the world.
Step-by-step explanation:
EDGE2021 :-)
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