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3 years ago

Helpppppppppppp 25pts!

Mathematics

2 answers:

kkurt [141]3 years ago

6 0

Answer:

Step-by-step explanation:

50-12 =38 might be wrong though but try it

Margarita [4]3 years ago

5 0

Answer:

Step-by-step explanation:

50/2=25-(12/2)=19

You might be interested in

Discribe two different strategies to add 16+35+24+14

Ira Lisetskai [31]

1st strategy: Add the first two terms and the last two.

16+35 + 24+14
51 + 38 = 89

2nd strategy: add the first and last term and the middle 2 terms.

16 + 35 + 24 + 14
30 + 59 = 89

5 0

3 years ago

Read 2 more answers

The students in Mr. Wilson's Physics class are making golf ball catapults. The

Mnenie [13.5K]

Answer:

Part a) About 48.6 feet

Part b) About 8.3 feet

Part c) The domain is $0 \leq x \leq 48.6\ ft$ and the range is $0 \leq y \leq 8.3\ ft$

Step-by-step explanation:

we have

$y=-0.014x^{2} +0.68x$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

where

x is the ball's distance from the catapult in feet

y is the flight of the balls in feet

Part a) How far did the ball fly?

Find the x-intercepts or the roots of the quadratic equation

Remember that

The x-intercept is the value of x when the value of y is equal to zero

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-0.014x^{2} +0.68x=0$

$a=-0.014\\b=0.68\\c=0$

substitute in the formula

$x=\frac{-0.68(+/-)\sqrt{0.68^{2}-4(-0.014)(0)}} {2(-0.014)}$

$x=\frac{-0.68(+/-)0.68} {(-0.028)}$

$x=\frac{-0.68(+)0.68} {(-0.028)}=0$

$x=\frac{-0.68(-)0.68} {(-0.028)}=48.6\ ft$

therefore

The ball flew about 48.6 feet

Part b) How high above the ground did the ball fly?

Find the maximum (vertex)

$y=-0.014x^{2} +0.68x$

Find out the derivative and equate to zero

$0=-0.028x +0.68$

Solve for x

$0.028x=0.68$

$x=24.3$

Alternative method

To determine the x-coordinate of the vertex, find out the midpoint between the x-intercepts

$x=(0+48.6)/2=24.3\ ft$

To determine the y-coordinate of the vertex substitute the value of x in the quadratic equation and solve for y

$y=-0.014(24.3)^{2} +0.68(24.3)$

$y=8.3\ ft$

the vertex is the point (24.3,8.3)

therefore

The ball flew above the ground about 8.3 feet

Part c) What is a reasonable domain and range for this function?

we know that

A reasonable domain is the distance between the two x-intercepts

$0 \leq x \leq 48.6\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 48.6 feet

A reasonable range is all real numbers greater than or equal to zero and less than or equal to the y-coordinate of the vertex

we have the interval -----> [0,8.3]

$0 \leq y \leq 8.3\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 8.3 feet

8 0

3 years ago

Isosceles trapezoid ABCD is shown below with a line EF drawn through its center. If the isosceles trapezoid is dilated using a s

Rus_ich [418]

Answer:

EF will contain the same points. When ABCD is dilated the points EF will stay on the line segments AB and CD.

Step-by-step explanation:

When the figure, ABCD, is dilated, the points EF will remain on the figure. I just had this question a few minutes ago.

5 0

3 years ago

Whats 4 plus 43242443534134

Svetlanka [38]

Answer:

43242443534138

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Helpppppppppppppppppppppppppppp

Oliga [24]

To find the area of a complex shape:

⇒ must split into simpler shapes

a rectangle of 8m by 7m
a rectangle of 2m by 8 m

Now let's find:

Area of a rectangle of 8m by 7m

$Area=8*7=56m^2$

Area of a rectangle of 2m by 8m

$Area = 2 * 8 = 16m^2$

Total Area = 56 + 16 = 72 m²

Answer: 72 m²

Hope that helps!

6 0

2 years ago