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kvasek [131]
3 years ago
13

Help me..........................​

Mathematics
1 answer:
rodikova [14]3 years ago
6 0

16. a
17. a
18. d
19. b
20. c
21. c
22. d
23. c
24. (please zoom in the circle so i can see the radius)

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Verify the conclusion of Green's Theorem by evaluating both sides of the equation for the field F= -2yi+2xj. Take the domains of
slega [8]

Answer:

hello your question is incomplete below is the complete question

verify the conclusion of Green's Theorem by evaluating both sides of the equation for the field F= -2yi+2xj. Take the domains of integration in each case to be the disk. R: x^2+y^2 < a^2 and its bounding circle C: r(acost)i+(asint)j, 0<t<2pi. the flux is ?? the circulation is ??

answer :  <em>attached below</em>

Step-by-step explanation:

Attached below is the required verification of the conclusion of Green's Theorem

In the attached solution I have  proven that Green's theorem ( ∫∫c F.Dr ) .

i.e. ∫∫ F.Dr = ∫∫r ( dq/dt - dp/dy ) dx dy = 4πa^2

               

6 0
3 years ago
When you cough,the radius of your trachea (windpipe) decreases,affecting the speed S of the air in the trachea. If r0 is the nor
elixir [45]

Answer: 2r(0)/3.

Step-by-step explanation:

So, we are given one Important data or o or parameter in the question above and that is the function of the form which is given below(that is);

S(r) = (r0 - r) ar^2 -----------------------------(1).

We will now have to differentiate S(r) with respect to r, so, check below for the differentiation:

dS/dr = 2ar (r0 - r ) + ar^2 (-1 ) ---------;(2).

dS/dr = 2ar(r0) - 2ar^2 - ar^2.

dS/dr = - 3ar^2 + 2ar(r0) ------------------(3).

Note that dS/dr = 0.

Hence, - 3ar^2 + 2ar(r0) = 0.

Making ra the subject of the formula we have;

ra[ - 3r + 2r(0) ] = 0. -------------------------(4).

Hence, r = 0 and r = 2r(0) / 3.

If we take the second derivative of S(r) too, we will have;

d^2S/dr = -6ar + 2ar(0). -------------------(5).

+ 2ar(0) > 0 for r = 0; and r = 2r(0)/3 which is the greatest.

6 0
3 years ago
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I need you guy’s help answer thanks so much
e-lub [12.9K]
I believe it’s C, hopefully this helps !!
6 0
3 years ago
If June has 3,756 toys and each bin can hold 30 toys what would be the left over amount of toys ?
Jlenok [28]
30 × 125 = 3750

125 bins can hold up to 3750 toys

3756 - 3750 = 6

6 toys will be left over

4 0
4 years ago
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What is the sum of the 2nd square number and the 5th cube number
lisabon 2012 [21]

Answer:

129

Step-by-step explanation:

4+125=129

7 0
3 years ago
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