There are two ways to work this out: normal variables or using "imaginary" numbers.
Normal variables:
![(7+2i)(3-i)\\(7*3)+[7*(-i)]+(3*2i)+[2i*(-i)]\\21-7i+6i-2i^{2}\\\\21-i-2i^{2}](https://tex.z-dn.net/?f=%20%287%2B2i%29%283-i%29%5C%5C%287%2A3%29%2B%5B7%2A%28-i%29%5D%2B%283%2A2i%29%2B%5B2i%2A%28-i%29%5D%5C%5C21-7i%2B6i-2i%5E%7B2%7D%5C%5C%5C%5C21-i-2i%5E%7B2%7D)
Imaginary numbers:
Using the result from earlier:
Now since
, then the expression becomes:
Answer:
B
Step-by-step explanation:
5.6 is bigger than 4.3
Answer is attached ! Hope it helps
I think your answer would be C.
1. find the LCD of 3 and 4 (12). so now your fractions are 5 4/12 and 3 9/12 perimeter is 2l + 2w so 2 (5 4/12) + 2( 3 9/12) = 10 4/12 + 7 6/12 = 17 10/12 or 17 5/6. this is reasonable because that the average perimeter of a sandbox.
2. LCD again is 12, so the fractions are 5 10/12 and 2 1/12. turn those into mixed fractions and get 70/12 and 25/12. 45/12 or 3 3/4. So she babysits 3 3/4 hours during the week.
3. The LCD for this is 8. now the fractions are 2/8 and 1 7/8 or 15/8. add 15/8 and 2/8 to get 17/8 or 2 1/8. He is using a total of 2 1/8 cups of flour.
4. 0.2
5. 0.054
6. 0.024
