The English alphabet contains 26 letters (a, b, c, ...y, z).
The digits from 0 to 9 are a total of 10.
A keycode contains 2 letters, and 3 numbers, for example:
AB 598; MM 139; NT 498; ...
So there are 26 possible choices for the first letter, which can combined with any of the 26 possible choices for the second letter, so there are a total of
26*26=676 possible pairs of letters.
Similarly, the 10 possible choices for the first number, which can be combined with the 10 possible choices for the second number, and the 10 possible choices for the third number make a total of :
10*10*10=1,000 possible triples of numbers.
Any of the 676 possible pairs of letters can be combined with any of the possible 1,000 triples of numbers. This makes a total of
676*1,000=676,000 keycodes.
Answer: 676,000
Answer:
25,000
Step-by-step explanation:
i think because 10 times 100 gets 1000 so now you have to do 250 times 100 to get 25,000
32, 38, so on. So its +4 then +8 then +12 +16 +20....
The graph represents p(x) = |x|
To graph r(x) and q(x), pick any values of x to graph (I'd pick the numbers on the x- scales, -6, -4, -2, 0, 2, 4, and 6)
As for explaining them, I'm sure something like "multiply the absolute value of x by -1/2" for describing q(x) is an acceptable answer.
Answer:
Step-by-step explanation:
This function has a slope of -1, a hole at x = -1, and a y-intercept of 5
