Answer:
C
Step-by-step explanation:
(2x + 3)^5 = C(5,0)2x^5*3^0 +
C(5,1)2x^4*3^1 + C(5,2)2x^3*3^2 + C(5,3)2x^2*3^3 + C(5,4)2x^1*3^4 + C(5,5)2x^0*3^5
Recall that
C(n,r) = n! / (n-r)! r!
C(5,0) = 1
C(5,1) = 5
C(5,2) = 10
C(5,3) = 10
C(5,4) = 5
C(5,5) = 1
= 1(2x^5)1 + 5(2x^4)3 + 10(2x^3)3^2 + 10(2x^2)3^3 + 5(2x^1)3^4 + 1(2x^0)3^5
= 2x^5 + 15(2x^4) + 90(2x^3) + 270(2x^2) + 405(2x) +243
= 32x^5 + 15(16x^4) + 90(8x^3) + 270(4x^2) + 810x + 243
= 32x^5 + 240x^4 + 720x^3 + 1080x^2 + 810x + 243
<span>4x+5/6x^2-x-12 - (5x/6x^2-x-12)
= (4x + 5 - 5x)/(</span>6x^2-x-12)
= (-x + 5) / (2x - 3)(3x +4)
<span>
answer
-x + 5
---------------------
</span> (2x - 3)(3x +4)
Answer:
either 34 or 214
Step-by-step explanation:
The answer is B) multiply 3 by 3. With that 2 on top, that doesn't mean 3 times 2, that means multiply 3 by itself, however many times the number says, if that makes sense. So if there's a 2 above the 3, then that would be 3*3. If it was a 5 instead of a two, that would mean 3*3*3*3*3. Not 3*5.
