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2 years ago

QUESTION IN PIC- 20 POINTS

Mathematics

1 answer:

sladkih [1.3K]2 years ago

7 0

Answer:

18 terms

Step-by-step explanation:

The first given sequence has first term a1=2 and common difference d=5. Its explicit formula is ...

an = 2 +5(n -1) = 5n -3

We want the n-th term of this sequence to be the same as the n-th term of the sequence defined by ...

an = 4n +15

We can find n that makes this true by setting the 'an' values equal:

an = an

5n -3 = 4n +15

n = 18 . . . . . . . . . . add 3-4n

The number of terms in each sequence is 18.

_____

<em>Additional comment</em>

The last term in each sequence is 87.

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Find the outlier of the set data 24,18,26,20,18,24,4,24

DIA [1.3K]

Answer:

Step-by-step explanation:

4 is way off of the other numbers.

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3 years ago

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Solve for x: -1/2(-4+2x) = -6 - 4x

antiseptic1488 [7]

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3 years ago

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sleet_krkn [62]

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2 years ago

98 Points! MATH SOLVING SYSTEMS OF LINEAR EQUATIONS

photoshop1234 [79]

Answer:

40 Tickets

80 Tickets

Step-by-step explanation:

To find how many tickets it will take to break even, we use the formula:

$Break Even In Units = \dfrac{FixedCost}{SalesPricePerUnit-VariableCost}$

Our variables are:

Fixed Cost = $200

Sales Price = $10

Variable Cost = $5

Let's plug in our values into the formula.

$Break Even In Units = \dfrac{200}{10-5}$

$Break Even In Units = \dfrac{200}{5}$

$Break Even In Units = 40$

So the class needs to sell a total of 40 Tickets to break even.

Since we know that it takes 40 tickets to break even a $200 Fixed cost. To make a profit of $200, we simply multiply the number of tickets sold by 2.

Number of tickets for $200 profit = 40 x 2

Number of tickets for $200 profit = 80 Tickets.

So the class needs to sell 80 Tickets to make a $200 Profit.

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2 years ago

In one day, a book store earned $199 in sales for 4 copies of a new cookbook and 5 copies of a new science fiction novel. On the

Marina86 [1]

Answer:

The cookbook costs $36 per copy while the science fiction costs $11 per copy

Step-by-step explanation:

Here in this question, we are interested in calculating the price of the cookbook and the price of the science fiction novel.

Since we do not know the price of each, we start by assigning variables to stand in for these unknown prices.

Let the price of the cookbook be $x , while the price of the science fiction be $y

Now, on the first day, 4 copies of the cookbook and 5 copies of the fiction;

mathematically that would be 4 * x and 5 * y

We add both and sum to be $199

Thus we have;

4x + 5y = 199 ••••••••••(i)

On the second day;

3 copies of cookbook 3 * x = 3x with 4 copies of science fiction 4 * y

Adding both yielded 152;

Thus, we have ;

3x + 4y = 152••••••••••(ii)

So we need to solve both equations simultaneously to get the values of x and y

4x + 5y = 199

3x + 4y = 152

Multiply equation i by 3 and equation ii by 4

3 * 4x + 5y = 199

4 * 3x + 4y = 152

12x + 15y = 597

12x + 16y = 608

Now, subtract multiplied equation ii from multiplied equation i

(12x-12x) + (15y-16y) = (597-608)

-y = -11

y = 11

To get x, simply substitute in any of the equations;

let’s use equation 1

4x + 5y = 199

4x + 5(11) = 199

4x + 55 = 199

4x = 199-55

4x = 144

x = 144/4

x = 36

8 0

3 years ago