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julia-pushkina [17]
2 years ago
7

QUESTION IN PIC- 20 POINTS

Mathematics
1 answer:
sladkih [1.3K]2 years ago
7 0

Answer:

  18 terms

Step-by-step explanation:

The first given sequence has first term a1=2 and common difference d=5. Its explicit formula is ...

  an = 2 +5(n -1) = 5n -3

We want the n-th term of this sequence to be the same as the n-th term of the sequence defined by ...

  an = 4n +15

We can find n that makes this true by setting the 'an' values equal:

  an = an

  5n -3 = 4n +15

  n = 18 . . . . . . . . . . add 3-4n

The number of terms in each sequence is 18.

_____

<em>Additional comment</em>

The last term in each sequence is 87.

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In a certain Algebra 2 class of 30 students, 19 of them play basketball and 12 of them play baseball. There are 8 students who p
Alenkinab [10]

Answer:

Probability that a student chosen randomly from the class plays basketball or baseball is  \frac{23}{30} or 0.76

Step-by-step explanation:

Given:

Total number of students in the class = 30

Number of students who plays basket ball = 19

Number of students who plays base ball = 12

Number of students who plays base both the games = 8

To find:

Probability that a student chosen randomly from the class plays basketball or baseball=?

Solution:

P(A \cup B)=P(A)+P(B)-P(A \cap B)---------------(1)

where

P(A) = Probability of choosing  a student playing basket ball

P(B) =  Probability of choosing  a student playing base ball

P(A \cap B) =  Probability of choosing  a student playing both the games

<u>Finding  P(A)</u>

P(A) = \frac{\text { Number of students playing basket ball }}{\text{Total number of students}}

P(A) = \frac{19}{30}--------------------------(2)

<u>Finding  P(B)</u>

P(B) = \frac{\text { Number of students playing baseball }}{\text{Total number of students}}

P(B) = \frac{12}{30}---------------------------(3)

<u>Finding P(A \cap B)</u>

P(A) = \frac{\text { Number of students playing both games }}{\text{Total number of students}}

P(A) = \frac{8}{30}-----------------------------(4)

Now substituting (2), (3) , (4) in (1), we get

P(A \cup B)= \frac{19}{30} + \frac{12}{30} -\frac{8}{30}

P(A \cup B)= \frac{31}{30} -\frac{8}{30}

P(A \cup B)= \frac{23}{30}

7 0
3 years ago
Solve for x 7 x + 15 equals 38
Galina-37 [17]

Answer:

x = 23/7

Step-by-step explanation:

7 x + 15 equals 38

7x+15 = 38

Subtract 15 from each side

7x+15-15 = 38-15

7x = 23

Divide each side by 7

7x/7 = 23/7

x = 23/7

6 0
4 years ago
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