The correct answer is 32 kilometers.
Answer:
5y + 3x + 9
Step-by-step explanation:
Whenever something is multiplied by the same variable, you can combine the coefficients. In this case, first you'd move the values with the same variable next to each other, for simplicity:
7y-2y+3x+3+6
Then, combine like terms.
5y+3x+3+6
5y+3x+9
Answer:
B. The mean amount of
emitted by the new fuel is actually lower than 89 kg but they fall to conclude it is lower than 89 kg
Step-by-step explanation:
A Type II error is the failure to reject a false null hypothesis.
Given the null and alternate hypothesis of a fuel company which wants to test a new type of gasoline designed to have lower
emissions.:
![H_0: \mu = 8.9 kg\\H_a: \mu < 8.9 kg \\\text{ (where \mu is the mean amount of CO_2 emitted by burning one gallon of this new gasoline)}](https://tex.z-dn.net/?f=H_0%3A%20%5Cmu%20%3D%208.9%20kg%5C%5CH_a%3A%20%5Cmu%20%3C%208.9%20kg%20%5C%5C%5Ctext%7B%20%28where%20%5Cmu%20is%20the%20mean%20amount%20of%20CO_2%20emitted%20by%20burning%20one%20gallon%20of%20this%20new%20gasoline%29%7D)
where
is the mean amount of
emitted by burning one gallon of this new gasoline.
If the null hypothesis is false, then:
![H_a: \mu < 8.9 kg](https://tex.z-dn.net/?f=H_a%3A%20%5Cmu%20%3C%208.9%20kg)
A rejection of the alternate hypothesis above will be a Type II error.
Therefore:
The Type II error is: (B) The mean amount of
emitted by the new fuel is actually lower than 89 kg but they fall to conclude it is lower than 89 kg.
150 miles= in 3 hours
150 miles/3 hours
= 50mph
Answer:
The result is
units.
Step-by-step explanation:
The coordinates for A and B:
A = (-2, 0)
B = (2, 2)
-To find the distance between A and B, you need the distance formula:
Where the first coordinate is
and the second coordinate is
.
-Use the coordinates A and B for the equation:
![d = \sqrt{(2+2)^2 + (2-0)^2}](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B%282%2B2%29%5E2%20%2B%20%282-0%29%5E2%7D)
-Then, you solve the equation:
![d = \sqrt{(2+2)^2 + (2-0)^2}](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B%282%2B2%29%5E2%20%2B%20%282-0%29%5E2%7D)
![d = \sqrt{(4)^2 + (2)^2}](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B%284%29%5E2%20%2B%20%282%29%5E2%7D)
![d = \sqrt{16 + 4}](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B16%20%2B%204%7D)
![d = \sqrt{20}](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B20%7D)
![d = 2\sqrt{5}](https://tex.z-dn.net/?f=d%20%3D%202%5Csqrt%7B5%7D)
So, therefore the distance is
units.