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WINSTONCH [101]
1 year ago
9

Name 4 ways you can use congruent parts of 2 triangles to prove that the triangles are congruent

Mathematics
1 answer:
Aloiza [94]1 year ago
4 0

Answer:

<h2><u><em>SSS (side, side, side)</em></u></h2><h2><u><em>SAS (side, angle, side)</em></u></h2><h2><u><em>ASA (angle, side, angle)</em></u></h2><h2><u><em>AAS (angle, angle, side)</em></u></h2><h2><u><em>HL (hypotenuse, leg)</em></u></h2>

<u><em></em></u>

Step-by-step explanation:

Name 4 ways you can use congruent parts of 2 triangles to prove that the triangles are congruent

SSS (side, side, side) ...

SAS (side, angle, side) ...

ASA (angle, side, angle) ...

AAS (angle, angle, side) ...

HL (hypotenuse, leg)

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How many months of the year have 28 days??
My name is Ann [436]
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3 years ago
(a) How many integers from 1 through 1,000 are multiples of 2 or multiples of 9?
DENIUS [597]

Answer:

(a)There are 500 integers from 1 through 1,000 are multiples of 2.

There are 111 integers from 1 through 1,000 are multiples of 9.

(b)0.611

Step-by-step explanation:

Given the set of Integers from 1 through 1000

The least multiple of 2 is 2 and the highest multiple of 2 in the interval is 1000.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 2,4,6,... is an Arithmetic Progression,

where first term, a =2, common difference, d =2

Nth term of an A.P,

U_n= a+(n-1)d\\1000=2+2(n-1)\\1000=2+2n-2\\1000=2n\\n=500

  • There are 500 integers from 1 through 1,000 are multiples of 2.

Similarly,

Given the set of Integers from 1 through 1000

The least multiple of 9 is 9 and the highest multiple of 9 in the interval is 999.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 9,18,27,... is an Arithmetic Progression,

where first term, a =9, common difference, d =9

Nth term of an A.P,

U_n= a+(n-1)d\\999=9+9(n-1)\\999=9+9n-9\\999=9n\\n=111

  • There are 111 integers from 1 through 1,000 are multiples of 9.

(b)Probability that an integer selected at random is a multiple of 2 or a multiple of 9.

There are a total of 1000 numbers between from 1 through 1,000

n(S)=1000

n(Multiples of 2)=500

n(Multiples of 9)=111

Therefore:

P(\text{Multiples of 9}) \:OR\: P(\text{Multiples of 2})=\frac{111}{1000} + \frac{500}{1000} \\=\frac{611}{1000} \\=0.611

7 0
3 years ago
How do I put y=90-15x in standard form
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The standard form: Ax + By = C


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<h3>15x + y = 90</h3>
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Your speed is 3.9 miles per hour
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2 years ago
F=6 and p = 2<br> 3f – 9p + 8 + f
Tamiku [17]

Answer:

14

Step-by-step explanation:

18-18+8+6

0+14

14

hope this helped!

6 0
3 years ago
Read 2 more answers
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