Expand the expression as
(<em>s</em> + 1)³/<em>s</em> ⁵ = (<em>s</em> ³ + 3<em>s</em> ² + 3<em>s</em> + 1)/<em>s</em> ⁵
… = 1/<em>s</em> ² + 3/<em>s</em> ³ + 3/<em>s</em> ⁴ + 1/<em>s</em> ⁵
Then taking the inverse transform, you get
LT⁻¹ [1/<em>s</em> ² + 3/<em>s</em> ³ + 3/<em>s</em> ⁴ + 1/<em>s</em> ⁵]
… = LT⁻¹ [1/<em>s</em> ²] + LT⁻¹ [3/<em>s</em> ³] + LT⁻¹ [3/<em>s</em> ⁴] + LT⁻¹ [1/<em>s</em> ⁵]
… = LT⁻¹ [1!/<em>s</em> ²] + 3/2 LT⁻¹ [2!/<em>s</em> ³] + 1/2 LT⁻¹ [3!/<em>s</em> ⁴] + 1/24 LT⁻¹ [4!/<em>s</em> ⁵]
… = <em>t</em> + 3/2 <em>t</em> ² + 1/2 <em>t</em> ³ + 1/24 <em>t</em> ⁴
Hi there!
Answer:
<u><em>=195x and x=195</em></u>
Step-by-step explanation:
Distributive property: a(b+c)=ab+ac
Multiply by the numbers.
39*5=195
195/5=39
195/39=5
5*39=195
=195x and x=195
Hope this helps!
-Charlie
Given:
The given statement are:
a. Eight less than the product of seven and x.
b. The sum of six and the product of three and d.
To find:
The expression for the given statements.
Solution:
a.
Product of 7 and x is 7×x = 7x.
Eight less than the product of seven and x is 7x - 8.
Therefore, the required expression for the statement "Eight less than the product of seven and x" is 7x-8.
b.
Product of 3 and d is 3×d = 3d.
The sum of six and the product of three and d is 6+3d.
Therefore, the required expression for the statement "The sum of six and the product of three and d" is 6+3d.
Answer:
The answer is A✔✔✔ Hope that helps!!!!
Step-by-step explanation:
When you are looking for perimeter you have to add all sides than the sum is your answer
