Answer:
position: (-6, -4)
range: 6
Step-by-step explanation:
The equation is that of a circle centered at (-6, -4) with a radius of √36 = 6. We presume that the "position" is that of the circle's center, and the "range" is the radius of the circle.
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The standard form equation of a circle with center (h, k) and radius r is ...
(x -h)^2 +(y -k)^2 = r^2
Matching parts of the equation, we find ...
h = -6, k = -4, r = √36 = 6.
Answer: 
Step-by-step explanation:
Given
The cylinder is 20 cm high
The radius of the cylinder is 
The total area of the figure is the sum of the rectangle and two circles
![\Rightarrow \text{Perimeter P=}2[h+2r]\\\Rightarrow P=2[20+6]\\\Rightarrow P=52\ cm](https://tex.z-dn.net/?f=%5CRightarrow%20%5Ctext%7BPerimeter%20P%3D%7D2%5Bh%2B2r%5D%5C%5C%5CRightarrow%20P%3D2%5B20%2B6%5D%5C%5C%5CRightarrow%20P%3D52%5C%20cm)
The total area of the figure is
Numbers are 416, 417 and 418
<u>Step-by-step explanation:</u>
Step 1:
Let the numbers be x, x + 1 and x + 2. Given that their sum is 1251.
⇒ x + x + 1 + x + 2 = 1251
⇒ 3x + 3 = 1251
⇒ 3x = 1248
⇒ x = 416
Step 2:
Find the other numbers.
⇒ x + 1 = 417 and x + 2 = 418
1B
2C
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