Question

Find the distance, c, between (2,-1) and (-1, 4) on the coordinate plane. Round to the nearest tenth

Answer 1

Answer:

c ≈ 5.8 units

Step-by-step explanation:

Calculate c using the distance formula

d = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }$

with (x₁, y₁ ) = (2, - 1 ) and (x₂, y₂ ) = (- 1, 4 )

c = $\sqrt{(-1-2})^2+(4-(-1))^2$

   = $\sqrt{(-3)^2+(4+1)^2}$

   = $\sqrt{9+5^2}$

    = $\sqrt{9+25}$

    = $\sqrt{34}$

    ≈ 5.8 units ( to the nearest tenth )