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3 years ago

Find the values of m so that the point (2,3) lies in the curve x^2+y^2+mx+2y-30=0.

Mathematics

1 answer:

mr_godi [17]3 years ago

7 0

Answer:

= your nose and eye and mouth

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A tortoise can reach speeds of 0.12 m/s. Work out the speed of a tortoise in

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3 years ago

I need help answering these 1. And 2. 10 points ⭐️ If helped

ratelena [41]

Well they are not in length

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4 years ago

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Let f(x) = -2x + 7 and g(x) = -6x + 3. Find fxg and state its domain.

marissa [1.9K]

Option D: $(f\times g)(x)=12 x^{2}-48 x+21$ ; all real numbers.

Explanation:

Given that the functions are $f(x)=-2 x+7$ and $g(x)=-6 x+3$

We need to determine the value of $(f\times g)(x)$ and its domain.

The value of $(f\times g)(x)$ :

The value of $(f\times g)(x)$ can be determined by multiplying the two functions.

Thus, we have,

$(f\times g)(x)=f(x)\times g(x)$

$=(-2x+7)(-6x+3)$

$=12x^2-6x-42x+21$

$(f\times g)(x)=12 x^{2}-48 x+21$

Thus, the value of $(f\times g)(x)$ is $(f\times g)(x)=12 x^{2}-48 x+21$

Domain:

We need to determine the domain of the function $(f\times g)(x)$

The domain of the function is the set of all independent x - values for which the function is real and well defined.

Thus, the function $(f\times g)(x)=12 x^{2}-48 x+21$ has no undefined constraints, the function is well defined for all real numbers.

Hence, Option D is the correct answer.

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3 years ago

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A quiz consists of 40 multiple choice questions, each with five possible answers, only one of which is correct. If a student g

Artist 52 [7]

Answer:

8 and 2.529

Step-by-step explanation:

The computation of the mean and the standard deviation is shown below:

Given that

Total number of questions is n = 40

The Probability of correct answer is p = $\frac{1}{5}$

So, the probability of the wrong answer is q = $1 - \frac {1}{5}$ = $\frac{4}{5}$

Moreover, this is the binomial distribution

Based on the above information

The mean is

$= n \times p$

$= 40\times \frac{1}{5}$

= 8

Now the variance is

$= 40\times \frac{1}{5} \times \frac{4}{5}$

= $\frac{32}{5}$

So, the standard deviation is

$= \sqrt{\frac{32}{5} }$

= 2.529

hence, the mean and the standard deviation is 8 and 2.529 respectively

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3 years ago

Find the values of m so that the point (2,3) lies in the curve x^2+y^2+mx+2y-30=0.​

Find the values of m so that the point (2,3) lies in the curve x^2+y^2+mx+2y-30=0.