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2 years ago

pls answer this Explain when you would use miles versus when you would use inches to reference a length measurement.

Mathematics

1 answer:

Allushta [10]2 years ago

6 0

Answer:

You would use miles when you are measuring long distances.

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Kristin paid $18.60 for 3 pounds of candy.

zvonat [6]

Answer:

$6.20 is the cost of candy per pound.

5/31 lbs of candy would be for $1.

Step-by-step explanation:

4 0

4 years ago

HELP NEEDED!!!

V125BC [204]

a) The formula for compound interest is:

Total = starting amount x (1 + interest rate)^ number of years

Using the given information you have:

1200 = 500 x (1+0.045)^x where x is the length of time you want to find.

1200 = 500 (1.045)^x

Divide both sides by 500:

2.4 = 1.045^x

Use natural logarithms:

ln(1.045^x) = ln(2.4)

Solve for x:

X = ln(2.4) / ln(1.045)

X = 19.889 years ( Round the answer as needed).

6 0

3 years ago

Use multiplication or division of power series to find the first three nonzero terms in the Maclaurin series for each function.

Lunna [17]

Answer:

The first three nonzero terms in the Maclaurin series is

$\mathbf{ 5e^{-x^2} cos (4x) }= \mathbf{ 5 ( 1 -9x^2 + \dfrac{115}{6}x^4+ ...) }$

Step-by-step explanation:

GIven that:

$f(x) = 5e^{-x^2} cos (4x)$

The Maclaurin series of cos x can be expressed as :

$\mathtt{cos \ x = \sum \limits ^{\infty}_{n =0} (-1)^n \dfrac{x^{2n}}{2!} = 1 - \dfrac{x^2}{2!}+\dfrac{x^4}{4!}-\dfrac{x^6}{6!}+... \ \ \ (1)}$

$\mathtt{e^{-2^x} = \sum \limits^{\infty}_{n=0} \ \dfrac{(-x^2)^n}{n!} = \sum \limits ^{\infty}_{n=0} (-1)^n \ \dfrac{x^{2n} }{x!} = 1 -x^2+ \dfrac{x^4}{2!} -\dfrac{x^6}{3!}+... \ \ \ (2)}$

From equation(1), substituting x with (4x), Then:

$\mathtt{cos (4x) = 1 - \dfrac{(4x)^2}{2!}+ \dfrac{(4x)^4}{4!}- \dfrac{(4x)^6}{6!}+...}$

The first three terms of cos (4x) is:

$\mathtt{cos (4x) = 1 - \dfrac{(4x)^2}{2!}+ \dfrac{(4x)^4}{4!}-...}$

$\mathtt{cos (4x) = 1 - \dfrac{16x^2}{2}+ \dfrac{256x^4}{24}-...}$

$\mathtt{cos (4x) = 1 - 8x^2+ \dfrac{32x^4}{3}-... \ \ \ (3)}$

Multiplying equation (2) with (3); we have :

$\mathtt{ e^{-x^2} cos (4x) = ( 1- x^2 + \dfrac{x^4}{2!} ) \times ( 1 - 8x^2 + \dfrac{32 \ x^4}{3} ) }$

$\mathtt{ e^{-x^2} cos (4x) = ( 1+ (-8-1)x^2 + (\dfrac{32}{3} + \dfrac{1}{2}+8)x^4 + ...) }$

$\mathtt{ e^{-x^2} cos (4x) = ( 1 -9x^2 + (\dfrac{64+3+48}{6})x^4+ ...) }$

$\mathtt{ e^{-x^2} cos (4x) = ( 1 -9x^2 + \dfrac{115}{6}x^4+ ...) }$

Finally , multiplying 5 with $\mathtt{ e^{-x^2} cos (4x) }$ ; we have:

The first three nonzero terms in the Maclaurin series is

$\mathbf{ 5e^{-x^2} cos (4x) }= \mathbf{ 5 ( 1 -9x^2 + \dfrac{115}{6}x^4+ ...) }$

7 0

3 years ago

Estimate the product of 403 × 581 by rounding to the nearest hundred. A. 300,000 B. 240,000 C. 30,000 D. 24,000

irga5000 [103]

Answer:

It would be b.

Step-by-step explanation:

403x581=234143 rounded to 240,000

Hope it helped brainiest plz

8 0

3 years ago

PLEASE HELP!!! First right answer gets brilliant. Can someone please help? It is due today!

yaroslaw [1]

Answer: i think it is : You are having disney spells

i think that is it

Step-by-step explanation:

6 0

3 years ago