Factor out a -5 of 2x-5

Complete each statement then state the property or properties illustrated by each statement on

VMariaS [17]

Answer:

(8n)(-77)=-77(n*8)

We move all terms to the left:

(8n)(-77)-(-77(n*8))=0

We add all the numbers together, and all the variables

8n(-77)-(-77(+n*8))=0

We multiply parentheses

-616n-(-77(+n*8))=0

We calculate terms in parentheses: -(-77(+n*8)), so:

-77(+n*8)

We multiply parentheses

-616n

Back to the equation:

-(-616n)

We get rid of parentheses

-616n+616n=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

the property is Associative Property

Step-by-step explanation:

this one was kinda hard pls let me know it its right or not

7 0

2 years ago

Help with math plssssss!

Olenka [21]

$\dfrac{x\sqrt3}{\sqrt{4x}}=\dfrac{x\sqrt3}{\sqrt4\cdot\sqrt{x}}=\dfrac{x\sqrt3}{2\sqrt{x}}=\dfrac{x\sqrt3\cdot\sqrt{x}}{2\sqrt{x}\cdot\sqrt{x}}=\dfrac{x\sqrt{3x}}{2x}=\dfrac{\sqrt{3x}}{2}\to\boxed{4.}\\\\Used:\\\\\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\\sqrt{a}\cdot\sqrt{a}=a$

6 0

2 years ago

Solve the inequality |3t+1| > 8.

arlik [135]

<h3>Solve the inequality |3t+1| > 8.</h3>

<h2>ANSWER</h2>

or

8 0

2 years ago

An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t

USPshnik [31]

The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

$\displaystyle\int_a^bf(x)\,\mathrm dx$

Split up the interval $[a,b]$ into $n$ equal subintervals,

$[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]$

where $a=x_0$ and $b=x_n$ . Each subinterval has measure (width) $\dfrac{a-b}n$ .

Now denote the left- and right-endpoint approximations by $L$ and $R$ , respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are $\{x_0,x_1,\cdots,x_{n-1}\}$ . Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, $\{x_1,x_2,\cdots,x_n\}$ .

So, you have

$L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)$
$R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)$

Now let $T$ denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

$T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)$

Factoring out $\dfrac12$ and regrouping the terms, you have

$T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)$

which is equivalent to

$T=\dfrac12\left(L+R)$

and is the average of $L$ and $R$ .

So the trapezoidal approximation for your problem should be $\dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2$

4 0

2 years ago

Renting a car costs $35.50 per day, plus 40¢ per mile. If a customer paid $131 for a 2-day rental, how many miles was the car dr

qwelly [4]

Subtract the fee from the total:

131- 35.50 = 95.50

Now divide that by the price per mile:

95.50/ 0.40 = 238.75

They drove 238.74 miles

6 0

2 years ago

Read 2 more answers