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Agata [3.3K]
2 years ago
8

Factor out a -5 of 2x-5

Mathematics
1 answer:
raketka [301]2 years ago
5 0

Answer:

2

a

x

−

5

a

−

10

x

+

25

Step-by-step explanation:

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Plz answer only if you know it's correct. willl give brainliest to best answer
just olya [345]

Answer:

i believe is is 3/2

Step-by-step explanation:

as y goes up 30 x goes over 20

30/20 simplified is 3/2

3 0
3 years ago
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How long will it take to fill the tank with 40 gallons of water? Explain your reasoning.
Vlada [557]

Answer:

Q1) Answer: After 3 minutes there will be 4.8 gallons of water in the fish tank. Q2) Answer: 40 gallons of water will be filled after 25 minutes.

8 0
3 years ago
Read 2 more answers
Can anyone help please?
katen-ka-za [31]

Answer:

  • A'(-3, 12)
  • B'(9, 6)
  • C'(-6, -6)

Step-by-step explanation:

Dilation about the origin multiplies each coordinate value by the dilation factor.

For dilation factor k, the new coordinates are ...

  (x, y) ⇒ (kx, ky)

Your dilation factor is 3, so the transformation is ...

  (x, y) ⇒ (3x, 3y)

  A(-1, 4) ⇒ A'(-3, 12)

  B(3, 2) ⇒ B'(9, 6)

  C(-2, -2) ⇒ C'(-6, -6)

5 0
2 years ago
Use the cross product property to solve each equation: 5/7 = x/9
enot [183]

Answer:

x = 45/7

Step-by-step explanation:

\frac{5}{7} =\frac{x}{9}

Here, you can more easily see what the fractions look like.

In order to cross-multiply, you have to multiply 5 with 9, and 7 with x.

45 = 7x

Then, you isolate x by dividing 7 on both sides:

45/7 = x

Hope I helped :)

8 0
3 years ago
Consider the following functions. f1(x) = x, f2(x) = x2, f3(x) = 2x − 4x2 g(x) = c1f1(x) + c2f2(x) + c3f3(x) Solve for c1, c2, a
bekas [8.4K]

9514 1404 393

Answer:

  • (c1, c2, c3) = (-2t, 4t, t) . . . . for any value of t
  • NOT linearly independent

Step-by-step explanation:

We want ...

  c1·f1(x) +c2·f2(x) +c3·f3(x) = g(x) ≡ 0

Substituting for the fn function values, we have ...

  c1·x +c2·x² +c3·(2x -4x²) ≡ 0

This resolves to two equations:

  x(c1 +2c3) = 0

  x²(c2 -4c3) = 0

These have an infinite set of solutions:

  c1 = -2c3

  c2 = 4c3

Then for any parameter t, including the "trivial" t=0, ...

  (c1, c2, c3) = (-2t, 4t, t)

__

f1, f2, f3 are NOT linearly independent. (If they were, there would be only one solution making g(x) ≡ 0.)

7 0
2 years ago
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