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Agata [3.3K]
3 years ago
8

Factor out a -5 of 2x-5

Mathematics
1 answer:
raketka [301]3 years ago
5 0

Answer:

2

a

x

−

5

a

−

10

x

+

25

Step-by-step explanation:

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The weight of a particle of unobtainium is 2.66 x 10−6oz. The weight of a grain of spice is 9.17 x 10−4oz. About how much more d
Semenov [28]

Answer:

D 9.1 x 10^(-4) oz

Step-by-step explanation:

9.17 x 10^(-4) oz - 2.66 x 10^(-6) oz =

= 9.17 x 10^(-4) oz - 0.0266 x 10^(-4) oz

= 9.1 x 10^(-4) oz

4 0
3 years ago
What two numbers add to equal ten and multiplies to equal negative seven?
lawyer [7]
Okay ShallBeTheLast, what we will do will involve a lot of simple plug and play kind of actions.
To start we must notice one number must be negative and the other should be positive, because the multiplied number is a negative.

Next, lets multiply number that have a sum of 10 (keep in mind one has to be negative and the other has to be positive).

-1 * 10 = -10 false
-2 * 12 = -24 false
-3 * 13 = -39 false
notice that no number working and it's only getting farther away.
There is no solution for this that involves to integers.

I think you might of wrote the question backwards.
If that is the case we would run numbers like.....
-1 * (-6) = 7 false
-2 * (-5) = 10 true!!!!

-2 and -5 would work
4 0
4 years ago
A 50-gal tank initially contains 20 gal of pure water. Salt- water solution containing 0.5 lb of salt for each gallon of water b
icang [17]

Answer:

x(15) = 21 lb

Step-by-step explanation:

Rate of change in volume of salt water solution = rate of volume incoming - rate of volume outgoing

                                dV/dt  = 4 - 2 =2gal/min

So, the equation for volume at cetain time t at given conditions and values becomes,

                                V(t) = 2t + V

                                V(t) = 2t + 20   gal-------------------euqation (1)

Rate of change in amount of salt = rate of salt in - rate of salt out

                                  dx/dt = {0.5*4} - {[x(t)/V(t)]*2}

                                  dx/dt = 2-2[(x(t))/(2t+20)]

                                  dx/dt = 2-[(x(t))/(v(t))] lb/min

Now, with integrating factor, we get

          exp[∫(1/(1+10))dt)] = t+10

the equation becomes

(t + 10)*x' + x = 2*(t+10)

((t+10)*x') = 2*(t+10)

(t+10)*x = t² + 20t + C

As x(0) = 0,

x(t) = (t²+20t)/(t+10)

x(15) = (15²+20*15)/(15+10)

x(15) = 21 lb

4 0
3 years ago
Which statement correctly identifies an asymptote of f (x) = StartFraction 16 x squared minus 35 Over x squared minus 5 EndFract
mezya [45]

Answer:

D

Step-by-step explanation:

Edge

8 0
3 years ago
Read 2 more answers
Find three consecutive odd integers such that the sum of the first and third equals the sum of the second and 29.
podryga [215]

Answer:

27, 29, 31

Step-by-step explanation:

We want to find a, b, c so that

a + c = b + 29

and

a = b - 2, c = b + 2

and

b is odd.

This results in

b - 2 + b + 2 = b + 29

with one solution:

b = 29.

6 0
4 years ago
Read 2 more answers
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