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bulgar [2K]
3 years ago
8

Ray BD bisects ABC so that m 2DBC = (x + 6)° and m ZABD = (2x – 12). What is x?

Mathematics
1 answer:
Ludmilka [50]3 years ago
5 0
C 16 is correct Bc if u solve it out it Becomes to 16 put -6 under 2 and 12 cross out 2-6 and add 12 and 6 witch gives u 16.
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[See Below]

Step-by-step explanation:

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When factoring a polynomial in the form ax2 + bx + c, where a, b, and c are positive real numbers, should the signs in the binom
gtnhenbr [62]

When factoring a polynomial in the form ax2 + bx + c, where a, b, and c are positive real numbers, the signs in the binomials should be both positive

<h3>What are quadratic equations?</h3>

Quadratic equations are second-order polynomial equations and they have the form y = ax^2 + bx + c or y = a(x - h)^2 + k

<h3>How to determine the true statement?</h3>

The form of the polynomial is given as:

ax2 + bx + c

Where a, b, and c are positive real numbers.

Since a, b, and c are positive real numbers. then the form of the expansion would be:

ax2 + bx + c = (dx + e)(fx + g)

<h3>Example to verify the claim</h3>

Take for instance, we have the following quadratic equation

x^2 + 6x +  8

Expand the equation

x^2 + 6x +  8 = x^2 + 4x + 2x +  8

Factorize the equation

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Hence, the signs in the binomials should be both positive

Read more about polynomials at:

brainly.com/question/4142886

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5 0
1 year ago
How is the Distributive Property used to simplify operations with scientific notation
Citrus2011 [14]

Answer:

See explanation

Step-by-step explanation:

Let a,b, and c be real numbers.

The distributive property says that:

a(b + c) = ab + ac

Assuming we want to simplify:

10(5*10^{-1}+150*10^{-3})

We apply the distributive property to get:

10(5*10^{-1}+150*10^{-3}) = 5*10^{-1} \times 10+150*10^{-3} \times 10

We can now use rules of exponents to simplify further:

10(5*10^{-1}+150*10^{-3}) = 5*10^{-1} \times 10^{1} +150*10^{-3} \times 10^{1}

10(5*10^{-1}+150*10^{-3}) = 5*10^{-1 + 1} +150*10^{-3 + 1}

10(5*10^{-1}+150*10^{-3}) = 5*10^{0} +150*10^{-2}

10(5*10^{-1}+150*10^{-3}) = 5*1+1.50*10^{-2}x {10}^{2}

10(5*10^{-1}+150*10^{-3}) = 5*1+1.50*10^{-2 + 2}

10(5*10^{-1}+150*10^{-3}) = 5+1.50*10^{0} = 6.5 \times  {10}^{0}

4 0
3 years ago
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